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3 years ago

The dimensions are 4ft by 3 1/3 ft. How much fencing does she need?

Mathematics

1 answer:

Anna11 [10]3 years ago

8 0

There isn't enough information to solve this problem we need to know how long the fence is

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Judy uses 7.5 pints of blue paint and white paint to paint her bedroom walls. 1/4 of this amount is blue paint, and the rest is

lianna [129]

Answer:

5.625 pints

Step-by-step explanation:

refer to pic

8 0

2 years ago

5x+4 HELP ME PLS it’s for a test I have right now

saveliy_v [14]

Answer:

Here is a graph of that equation.

Let me know if you need more help! :)

4 0

2 years ago

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marusya05 [52]

Answer:

jhliyuglkiygedrloqayfgwelJUQHAUGWDkutygsk,Hgkuyt

Step-by-step explanation:

3 0

2 years ago

Keegan is printing and selling his original design on t-shirts. He has concluded that for x shirts, in thousands sold his total

Katarina [22]

Answer:

t-shirts: 2790

profit: $12209

Step-by-step explanation:

Given the function:

p(x) = -x³ + 4x² + x

we want to maximize it.

The following criteria must be satisfied at the maximum:

dp/dx = 0

d²p/dx² < 0

dp/dx = -3x² + 8x + 1 = 0

Using quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 -4(a)(c)}}{2(a)}$

$x = \frac{-8 \pm \sqrt{8^2 -4(-3)(1)}}{2(-3)}$

$x = \frac{-8 \pm 8.72}{-6}$

$x_1 = \frac{-8 + 8.72}{-6}$

$x_1 = -0.12$

$x_2 = \frac{-8 - 8.72}{-6}$

$x_2 = 2.79$

d²p/dx² = -6x + 8

d²p/dx² at x = -0.12: -6(-0.12) + 8 = 8.72 > 0

d²p/dx² at x = 2.79: -6(2.79) + 8 = -8.74 < 0

Then, he should prints 2.79 thousands, that is, 2790 t-shirts to make maximum profits.

Replacing into profit equation:

p(x) = -(2.79)³ + 4(2.79)² + 2.79 = 12.209

that is, $12209

3 0

3 years ago

What the recursive formula for the sequence

klemol [59]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})$

so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

$\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}$

just a quick note on notation:

$\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}$

8 0

3 years ago