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2 years ago

F( x) = 8x – 9 when x=3

Mathematics

2 answers:

Nady [450]2 years ago

7 0

15 but it in a calculator

Elan Coil [88]2 years ago

3 0

Answer:

f = 5, x = 3.

Step-by-step explanation:

8x = 24

24 - 9 = 15.

3(5) = 15.

hope this helps.

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3 years ago

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If a person flips a coin and then rolls a six dash sided die, describe the sample space of possible outcomes using Upper H comm

xenn [34]

Answer:

Sample Space (S) = { (1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T) }

Step-by-step explanation:

If a person flips a coin; the possible outcomes of flipping a coin are { Head (H), Tail (T) }

If a person rolls a six dash side die, the possible outcomes of rolling a dice are { 1, 2, 3, 4, 5, 6 }

Now, If a person flips a coin and then rolls a six dash side die;

The Sample Space (S) which is the set of all the possible outcomes of the activities carried out can be described as follows:

DIE COIN →

↓

H T

1 (1,H) (1,T)

2 (2,H) (2,T)

3 (3,H) (3,T)

4 (4,H) (4,T)

5 (5,H) (5,T)

6 (6,H) (6,T)

Sample Space (S) = { (1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T) }

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3 years ago

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

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3 years ago

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vovikov84 [41]

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3 years ago