Answer:
The answer to your question is below
Explanation:
Data 1
mass 1 = 250
mass 2 = 250 kg
gravity constant = 6.67 x 10⁻¹¹ Nm²/kg²
distance = 8 m
Formula
Substitution
Result
F = 0.000000065 N
Data 2
mass 1 = 1000 kg
mass 2 = 1000 kg
distance = 5 m
Substitution
Result
F = 0.000002667 N
If you have fifty 15-ohm resistors all connected in parallel, their "effective" resistance is (15/50) = 0.3 ohms.
Current = (voltage) / (resistance)
Current = (115 V) / (0.3 ohm)
<em>Current = 383.3 Amperes</em>
This is an interesting question, with a VERRRRY interesting answer. The fuse or circuit breaker that feeds the outlet where these lights are plugged in is most likely rated 15 or 20 or 25 Amperes, and it trips immediately.
But let's say it doesn't ... let's say the juice just keeps on flowing.
Power = (voltage) x (current)
These lights use energy at the rate of (115V)x(383.3A) = 44,083 watts. This is roughly the same as the power used to run 22 toasters or 37 blow-dryers, all at the same time. AND ... the lights are going to produce almost as much <u>heat</u> as 22 toasters or 37 blow-dryers all running at the same time. The lights will probably burn the house down before long.
If electrical energy costs 20¢ per kilowatt-hour in this city, then running those lights for ONE HOUR is going to cost $8.82 !
All in all, it will be a good idea to unplug the Christmas tree lights when the family goes to bed.
<span>The winds and currents flow faster at the equator than the poles because the equator is much warmer than the poles. Also the Earth's rotation is much faster at the equator than at the poles.
-I hope this is the answer you are looking for.</span>
Answer:
The energy loss due to friction is 9465 J.
Explanation:
The given data :-
Mass of roller (m) = 500 kg.
The speed of roller coaster at height 27 m = 5.6 m/s.
Initial height of roller( h ) = 27 m.
The speed of roller coaster at bottom = 22 m/s.
Initial energy of roller at a height 27 m.
E₁ = K.E + P.E
E₁ = = = 7840 + 132435
E₁ = 140,275 J
The energy of roller at a height 2 m.
E₂ = K.E + P.E
E₂ = = = 121000 + 9810
E₂ = 130,810 J
The energy loss due to friction = E₁ - E₂ = 140,275 - 130,810 = 9465 J.
Answer:
Using your right-hand: point your index finger in the direction of the charge's velocity, v, (recall conventional current). Point your middle finger in the direction of the magnetic field, B. Your thumb now points in the direction of the magnetic force, F.
Cheers!