Answer:
0.25 kg m^2
Explanation:
mass of each , m = 500 g = 0.5 kg
distance, r = 50 cm = 0.5 m
Moment of inertia about the axis passing through one corner and perpendicular to the plane of triangle
I = mr^2 + mr^2
I = 2 mr^2
I = 2 x 0.5 x 0.5 x 0.5
I = 0.25 kgm^2
Answer:
The atmospheric pressure is
.
Explanation:
Given that,
Atmospheric pressure
drop height h'= 27.1 mm
Density of mercury 
We need to calculate the height
Using formula of pressure

Put the value into the formula



We need to calculate the new height




We need to calculate the atmospheric pressure
Using formula of atmospheric pressure

Put the value into the formula


Hence, The atmospheric pressure is
.
Answer:
V = 0.39 m/s
Explanation:
Given that,
Mass of hockey puck, m = 0.2 kg
Mass of goalie = 40 kg
Speed of hockey puck, v = 80 m/s
We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :

So, the required speed is 0.39 m/s.
Kinetic energy = mass time squared speed divided by 2
W=mv^2/2 = 50*10*10/2 = 2500 J