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Alik [6]
3 years ago
11

A 0.2 kg hockey puck moving at 80 m/s is caught by a 40 kg goalie at rest. With what speed does the goalie slide on the slide?

Physics
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

V = 0.39 m/s

Explanation:

Given that,

Mass of hockey puck, m = 0.2 kg

Mass of goalie = 40 kg

Speed of hockey puck, v = 80 m/s

We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :

mv=(M+m)V\\\\V=\dfrac{mv}{M+m}\\\\V=\dfrac{0.2\times 80}{0.2+40}\\\\V=0.39\ m/s

So, the required speed is 0.39 m/s.

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A light source emits light with dominant wavelengths in the range of 650 to 690 nm. what is the principle color of light emitted
dsp73

Answer:

Please see below as the answer is self-explanatory.

Explanation:

  • The visible range extends roughly from 400 nm (violet) to 700 nm (red).
  • Below the violet is the ultra-violet spectrum (with higher energy) and above red, we have the infra-red spectrum.
  • The wavelengths in the range of 650 to 690 nm have red as the dominant color.
6 0
3 years ago
¿Qué resistencia debe ser conectada en paralelo con una de 20 Ω para hacer una
ValentinkaMS [17]

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

5 0
3 years ago
Identify the energy transformations in the image below:
Masteriza [31]

Answer:

B. Chemical to Electrical to Radiant

Explanation:

8 0
3 years ago
The drive chain in a bicycle is applying a torque of 0.850 nm to the wheel of the bicycle. treat the wheel as a hoop with a mass
BlackZzzverrR [31]
The equivalent of Newton's second law for rotational objects is given by:
\tau = I \alpha
where
\tau is the net torque acting on the object
I is its moment of inertia
\alpha is its angular acceleration

For a hoop rotating around its perpendicular axis, the moment of inertia is
I=mr^2
where m is the mass and r the radius. By using the data of the wheel, m=0.750 kg and r=33.0 cm=0.33 m, we find
I=mr^2 = (0.750 kg)(0.33 m)^2=0.082 kg m^2

and since the torque is \tau=0.850 Nm, the angular acceleration of the wheel is
\alpha= \frac{\tau}{I}= \frac{0.850 Nm}{0.082 km m^2}=10.37 rad/s^2
6 0
4 years ago
Describe the conditions necessary for sublimation to occur.
lozanna [386]
<span>To answer this question with specific values, you would need a phase diagram for the substance in question. In more general terms, the pressure needs to be lower than the pressure of the triple point, the substance must be present in its solid state, and the temperature must rise high enough to produce a gas.</span>
7 0
3 years ago
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