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wlad13 [49]
1 year ago
11

Define resistance of a conductor. State the factors on which resistance of a conductor depends.

Physics
1 answer:
e-lub [12.9K]1 year ago
5 0
<h3>Answer:</h3>

1. Resistance is the opposition offered in a path of flow of current by the atoms or molecules of the conductor.

Factors on which resistance of a conductor depends are:

<h3 />
  • Length R \propto l

  • Area of cross section R \propto \dfrac{1}{A}

  • Nature of the material

2. Rheostat is used to change the resistance without changing the voltage source in an electric circuit.

3.

Given :

\dashrightarrow  l = 50 m

\dashrightarrow  A = 0.01 {mm}^{2}

\dashrightarrow  A = 0.01 \times  {10}^{ - 6}  \:  {m}^{2}

\dashrightarrow   \rho = 5 \times  {10}^{ - 8}          \: \Omega \: m

We know that,

\dashrightarrow  R =  \rho \dfrac{l}{A}

\dashrightarrow  R =  5  \times  {10}^{ - 8} \bigg(\dfrac{50}{0.01 \times  {10}^{ - 6} } \bigg)

\dashrightarrow  { \pink{ \underline{ R = 250  \: \Omega }}}

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Galactic Alliance Junior Mission Officer (GAJMO) Bundit Nermalloy is predicting the kinetic energy of a supply spacecraft, which
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the ship's energy is greater than this and the crew member does not meet the requirement

Explanation:

In this exercise to calculate kinetic energy or final ship speed in the supply hangar let's use the relationship

                W =∫ F dx = ΔK

                 

Let's replace

             

          ∫ (α x³ + β) dx = ΔK

         α x⁴ / 4 + β x = ΔK

           

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         x (α x³ + β) = K_{f} - K₀

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Let's calculate

        K_{f}  = 2.7 10¹¹ + 7.5 10⁴ (6.1 10⁻⁹ (7.5 10⁴) 3 -4.1 10⁶)

        Kf = 2.7 10¹¹ + 7.5 10⁴ (2.57 10⁶ - 4.1 10⁶)

        Kf = 2.7 10¹¹ - 1.1475 10¹¹

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In the problem it indicates that the maximum energy must be 10¹⁰ J, so the ship's energy is greater than this and the crew member does not meet the requirement

We evaluate the kinetic energy if the System is well calibrated

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                K_{f} = K₀ + x F₀

We calculate

              K_{f} = 2.7 10¹¹ -7.5 10⁴ 3.5 10⁶

               K_{f} = (2.7 -2.625) 10¹¹

              K_{f} = 7.5 10⁹ J

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