Consider the following formula to find the circumference of circle
C= 2^_r
here r is radius of circle
the radius of circular is 25 ft.
Therefore circumference is as follows
C = 2^_r
= 2 × 3.14 (25)
= 157.
circumference of circle feet is 157 × 12 inches.
The answer is C
The answer is C because the function form for a linear function is f(x) = ax+b and the answer C has x which is the slope and -3 which would represent the y-intercept also known as b
Answer:
neither
Step-by-step explanation:
Take out 5 as a common factor. It will be easier to look at.
5(5c^2 + 11c + 6)
5(5C +6 )(c + 1 )
Now you can put the 5 inside.
(25c + 30)(c + 1) is one answer.
(5c + 6)(5c + 5) is another.
The answer is multiplying binomials. There is nothing that that is squared and the answers are not conjugates. They are two binomials multiplied together.
The answer is: "
40 cm " .
_________________________________________________________<u>Note</u>:_________________________________________________________
;
Solve for "x" (in "cm" ) ;
→ 5x = 200 * 1 ;
→ 5x = 200 ;
Divide each side of the equation by "5" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 5x / 5 = 200 / 5 ;
to get:
→ x = 40 .
___________________________________________________________The answer is: "
40 cm " .
___________________________________________________________
Answer:
The correct option is (b).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The confidence interval for population mean can be computed using either the <em>z</em>-interval or <em>t</em>-interval.
The <em>t</em>-interval is used if the following conditions are satisfied:
- The population standard deviation is not known
- The sample size is large enough
- The population from which the sample is selected is normally distributed.
For computing a (1 - <em>α</em>)% confidence interval for population mean , it is necessary for the population to normally distributed if the sample selected is small, i.e.<em>n</em> < 30, because only then the sampling distribution of sample mean will be approximated by the normal distribution.
In this case the sample size is, <em>n</em> = 28 < 30.
Also it is provided that the systolic blood pressure is known to have a skewed distribution.
Since the sample is small and the population is not normally distributed, the sampling distribution of sample mean will not be approximated by the normal distribution.
Thus, no conclusion can be drawn from the 90% confidence interval for the mean systolic blood pressure.
The correct option is (b).