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2 years ago

Example of energy transfer from potential to kinetic and back

1 answer:

5 0

Swimmer and Divers. The Potential energy is transferred into Kinetic energy, and allows the diver to submerge into the water. The Kinetic energy then allows the diver to submerge and dive into the water. Potential energy however, is needed to allow the diver to get back out of the water after diving to get up and go and dive again, and then the Kinetic energy is transferred back to Potential energy to repeat the process.

Hope :) -Emilie Xo this is right and it helps! Xo

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One side of the moon always faces Earth because the time it takes the moon to spin on its axis is blank the time it takes the mo

Kamila [148]

The word to fill in the blank is "equal". Because the time taken to rotate (spin on its axis) is equal to the time of revolution (going around the earth), this means that both have the same rate of angular rotation. So for every bit that the moon goes around its orbit around earth, the moon itself rotates accordingly to present the exact same side to earth.

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3 years ago

Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in ca

OverLord2011 [107]

Answer:

E = -4000 N / C

Explanation:

The potential and electric field are related

V = - E s

E = - V / s

we reduce the magnitudes to the SI system

s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

E = - 16 /0.004

E = -4000 N / C

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3 years ago

On Earth, friction can be _____ but not removed.

Whitepunk [10]

Answer:

reduced

Explanation:

The use of bearing surfaces that are themselves sacrificial, such as low shear materials, of which lead/copper journal bearings are an example

4 0

2 years ago

Una locomotiva traina un solo vagone, che ha la sua stessa massa, con la forza di

gregori [183]

Answer:

c) F = 16000 N

Explanation:

For this exercise we use Newton's second law

F = ma

they tell us that adding the other wagons the acceleration of the locomotive must be maintained

F = m a

by adding the other four wagons

mass = 4 no

therefore to maintain the force you must also raise the same factor

Fe = 4Fo

Fe = 4 4000

F = 16000 N

3 0

3 years ago

A circular loop in the plane of a paper lies in a 0.45 T magnetic field pointing into the paper. The loop's diameter changes fro

Amanda [17]

Answer:

(A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

Explanation:

Given that,

Magnetic field = 0.45 T

The loop's diameter changes from 17.0 cm to 6.0 cm .

Time = 0.53 sec

(A). We need to find the direction of the induced current.

Using Lenz law

If the direction of magnetic field shows into the paper then the direction of the induced current will be clockwise.

(B). We need to calculate the magnetic flux

Using formula of flux

$\phi_{1}=BA\cos\theta$

Put the value into the formula

$\phi_{1}=0.45\times(\pi\times(8.5\times10^{-2})^2)\cos0$

$\phi_{1}=0.01021\ Wb$

We need to calculate the magnetic flux

Using formula of flux

$\phi_{2}=BA\cos\theta$

Put the value into the formula

$\phi_{2}=0.45\times(\pi\times(3\times10^{-2})^2)\cos0$

$\phi_{2}=0.00127\ Wb$

We need to calculate the magnitude of the average induced emf

Using formula of emf

$\epsilon=-N(\dfrac{\Delta \phi}{\Delta t})$

Put the value into t5he formula

$\epsilon=-1\times(\dfrac{0.00127-0.01021}{0.53})$

$\epsilon=0.016867\ V$

$\epsilon=16.87\ mV$

(C). If the coil resistance is 2.5 Ω.

We need to calculate the induced current

Using formula of current

$I=\dfrac{\epsilon}{R}$

Put the value into the formula

$I=\dfrac{0.016867}{2.5}$

$I=0.00675\ A$

$I=6.75\ mA$

Hence, (A). The direction of the induced current will be clockwise.

(B). The magnitude of the average induced emf 16.87 mV.

(C). The induced current is 6.75 mA.

5 0

3 years ago