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3 years ago

9

Which situation is an example of increasing potential energy? Question 4 options: A. a cat jumping from a tree B. pulling a wago

n uphill B. a bicyclist stopping at a stop sign C.\emptying a bucket of water

2 answers:

enyata [817]3 years ago

5 0

The answer to this is a

jeka943 years ago

4 0

Pulling an wagon uphill I believe.

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A flow is isentropically expanded to supersonic speeds in a convergent-divergent nozzle. The reservoir and exit pressures are 1.

Kamila [148]

Answer:

Ae/A* = 1.115

Explanation:

Let the reservoir pressure be $p_0$

Let the exit pressure be $p_e$

Ratio of reservoir pressure and exit pressure

$\frac{p_o}{p_e} = \frac{1}{0.3143}$

= 3.182

For the above value of pressure ratio

Obtain the area ratio from the isentropic flow table

Ae/A* = 1.115

The value of pressure ratio is Ae/A* = 1.115

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3 years ago

arrange the following sound waves according to speed from the slowest to the fastest: The sound waves in steel,The sound waves i

Paladinen [302]

The basic concept that needs to be understood is that sound travels faster through a dense medium. Now if we check the options given in the question, then they should be arranged in the manner given below.
1. <span>The sound waves in hot air.
2. </span><span>The sound waves in cold air.
3. </span>The sound <span>waves in water.
4. </span><span>The sound waves in steel.</span>

8 0

3 years ago

A ball thrown at 4 meters/second exerts 200 Newtons of force. The mass of the ball is:

Harlamova29_29 [7]

Answer:

50

Explanation:

200 divided by 4 gives you the mass of 50

5 0

3 years ago

A 3.00 kg object is fastened to a light spring, with the intervening cord passing over a pulley. The pulley is frictionless, and

finlep [7]

Answer:

Part a)

k = 588.6 N/m

Part b)

v = 0.7 m/s

Explanation:

As we know that initially block is at rest

now if block is released from rest then it will go down by 10 cm and again comes to rest

so here we have

Part a)

Work done by gravity + work done by spring force = change in kinetic energy

$W_g + W_{spring} = 0 - 0$

$mg(0.10) + \frac{1}{2}k(0^2 - 0.10^2) = 0$

$3(9.81)(0.10) - \frac{1}{2}k(0.10)^2 = 0$

$k = 588.6 N/m$

Part b)

Now when spring is stretch by x = 5 cm then the speed of the block is given as

$mgx' + \frac{1}{2}k(0^2 - x'^2) = \frac{1}{2}mv^2 - 0$

here we have

$x' = 0.05 m$

$3(9.81)(0.05) - \frac{1}{2}(588.6)(0 - 0.05^2) = \frac{1}{2}(3) v^2$

$1.4715 - 0.736 = 1.5 v^2$

$v = 0.7 m/s$

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3 years ago

Question: <br>Define work.<br>

rjkz [21]

Answer:

<u>Work</u>, in physics, refers to the measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

4 0

3 years ago