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Flauer [41]
3 years ago
13

Find the coordinates of the endpoint of the image?

Mathematics
1 answer:
ra1l [238]3 years ago
5 0

Given:

The graph of a line segment.

The line segment AB translated by the following rule:

(x,y)\to (x+4,y-3)

To find:

The coordinates of the end points of the line segment A'B'.

Solution:

From the given figure, it is clear that the end points of the line segment AB are A(-2,-3) and B(4,-1).

We have,

(x,y)\to (x+4,y-3)

Using this rule, we get

A(-2,-3)\to A'(-2+4,-3-3)

A(-2,-3)\to A'(2,-6)

Similarly,

B(4,-1)\to B'(4+4,-1-3)

B(4,-1)\to B'(8,-4)

Therefore, the endpoint of the line segment A'B' are A'(2,-6) and B'(8,-4).

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Solve A = P(1 + rt) for t
tino4ka555 [31]
A=P(1+rt)
A/P=1+rt
A/P-1=rt
AP-P/Pr = t
A-1/r=t
7 0
3 years ago
Read 2 more answers
Fiona wants to estimate the product (8.7)(3.0). Which expression shows each factor rounded to the nearest whole number?
borishaifa [10]
(9)(3) would be the expression for the factors rounded to the nearest whole numbers.
I hope I correctly answered your question and that this helps.
5 0
3 years ago
You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s
fredd [130]

Answer:

Time spent rowing down stream =100\ seconds

Speed of boat in still water =14\ ms^{-1}

Step-by-step explanation:

Let speed of boat in still water be = x\ ms^{-1}

Speed of current = 10\ ms^{-1}

Speed of boat down stream = \textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}

Distance rowed down stream = 2400 m

Time spent rowing down stream = \frac{Distance}{Speed}=\frac{2400}{x+10}\ s = \frac{Distance}{Speed}=\frac{2400}{x+10}\ s

Speed of boat up stream = \textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}

Distance rowed up stream = \frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m

Time spent rowing up stream = \frac{Distance}{Speed}=\frac{400}{x-10}\ s

We know that,

\textrm{Time spent rowing down stream =Time spent rowing up stream}

So,

\frac{2400}{x+10}=\frac{400}{x-10}

Cross multiplying

2400(x-10)=400(x+10)

Dividing both sides by 400

\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}

6(x-10)=x+10

6x-60=x+10

Adding 60 to both sides.

6x-60+60=x+10+60

6x=x+70

Subtracting both sides by x

6x-x=x+70-x

5x=70

Dividing both sides by 5.

\frac{5x}{5}=\frac{70}{5}

∴ x=14

Speed of boat in still water =14\ ms^-1

Time spent rowing down stream =\frac{2400}{14+10}=\frac{2400}{24}=100\ s

3 0
3 years ago
X=2y=14 and x-3y=-11
levacccp [35]
X - 2y= 14
x - 3y= - 11   | * ( -1)

x - 2y = 14
-x + 3y= 11
----------------
/    y= 25

x - 2*25= 14
x - 50 =14
x= 14+50
x=64

7 0
3 years ago
X/2.1 = -1.8<br><br> Show your work and check it (write it out plz)
Lerok [7]
X = -1.8 * 2.1
x = 3.78

don't know how i can write it longer
7 0
3 years ago
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