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fomenos
3 years ago
14

karen brought 3/8 of a gallon of ice tea to a party. Robin brought 15/16 of a gallon of ice tea to the same party. How much ice

tea did they have together?
Mathematics
1 answer:
Rudiy273 years ago
7 0

Answer:

1  5/16 gallon

Step-by-step explanation:

Gallon of ice brought by Karen = 3/8

Gallon of ice brought by Robin = 15/16

Total ice team brought by them is sum of Gallon of ice brought by Karen + Gallon of ice brought by Robin

Total ice team brought by Karen and Robin = 3/8 + 15/16

=>  3*2/8*2 + 15/16

we are multiplying with 2 both numerator and denominator in 3/8 so sas the denominator becomes 16 as in other fraction denominator is 16

=> 6/16 + 15/16

=> (6+15)/16 = 21/16

since 21/16 is improper fraction, converting it in mixed fraction we have

21/16 = 1  5/16 gallon

Thus , Karen and Robin have 1  5/16 gallon ice tea together.

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A right rectangular prism is shown. The two dimensional net is also shown. Find the surface area of this prism.
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Hey!

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5 0
3 years ago
Find the base of an isosceles triangle whose area is 60 cm² and the length of one of its equal sides is 13 cm. ​
Kobotan [32]

Answer:

Base = 24 cm or 10cm

Step-by-step explanation:

REMEMBER:
An isosceles triangle ABC with base BC = ‘b' & height AD = ‘h' & its equal sides =13 cm & area = 60 cm²

Using the formulas

A=\frac{bh_b}{2}

h_b=\sqrt{a^2-\frac{b^2}{4} }

There are 2 solutions for b

b=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2+\sqrt{13^4-4*60^2} } } ≈ 10cmb=2\sqrt{2}   \frac{A}{\sqrt{a^2+\sqrt{a^4-4A^2} } } =2*\sqrt{2} *\frac{60}{\sqrt{13^2-\sqrt{13^4-4*60^2} } }=24cm

Less complex:

Area of a triangle = 1/2 * b * h = 60

=> h = 120/b

In right triangle ABD

13² = h² + b² /4 ( by Pythagoras law)

=>169 = 120²/b² + b²/4

=>676 b² = 57600 + b^4

=> b^4 - 676 b² + 57600 = 0

=> b² = 676 +- √(676² - 4*57600) / 2

=> b²= 676 +- √(226576) /2

=> b² = (676 +- 476 )/2

=> b² = 1152/2 , 200 /2

=> b² = 576 , 100

=> b = 24, 10

So, Base = 24 cm or 10cm

4 0
2 years ago
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