The question is asking to state the expression for the volume of the pyramid base on the side of the pyramid, in my further research and calculation, I would say that the answer would be V= 1/2s^3. I hope you are satisfied with my answer and feel free to ask for more
Answer:
3(34) + 20 -> Angle 6 = 122
2(34) - 10 -> Angle 3 = 58
Step-by-step explanation:
Since measure of angle 2 is equal to measure of angle 6, and measure of angle 7 is equal to measure of angle 3, we can determine the angle measures for angle 3 and angle 6.
First, we solve for x by adding together the two equations and setting it equal to 180 because of the supplementary angles theorem.
3x + 20 + 2x - 10 = 180
Combine like terms.
5x + 10 = 180
Subtract 10, then divide by 5 on both sides.
5x = 170
x = 34
Now we can plug the x value into the equations.
3(34) + 20 -> Angle 6 = 122
2(34) - 10 -> Angle 3 = 58
#teamtrees #WAP (Water And Plant)
Answer:
The number of children was 170 and adults was 368.
Step-by-step explanation:
To clarify we'll call children by 'c' and adults by 'a'. The amount of people in the pool should be the sum of adults and children, so:
a + c = 538
The receipts for the adimission should total the amount of tickets from children and adults multiplied by the price of each ticket, so:
1.75*c + 2.25*a = 1125.5
We now have two equations and two variables. Using the first equation we can isolate the 'a' variable and use it on the second equation to find an answer. We then have:
a + c = 538
a = 538 - c
Using it on the second equation:
1.75*c + 2.25*(538-c) = 1125.5
1.75*c + 1210.5 - 2.25*c = 1125.5
1.75*c - 2.25*c = 1125.5 - 1210.5
-0.5*c = -85
c = -85/(-0.5) = 170
Using this value on the first equation:
a = 538 - 170 = 368
Use pythagoreom thereom, so: a^2+b^2+c^2. a is the 48 inches, and b is 36. square both, add both, then square root the whole answer to solve for c.