Answer:
Methods of soil conservation are listed below.
Explanation:
The major sources of soil erosion include water,wind and tillage. In order to mitigate or prevent soil erosion, some of the following techniques can be implemented:
- <u>Contour Farming: </u>Planting in row patterns that run level around a hill — as opposed to the up and down the slope pattern.This reduces runoffs and consequently water erosion.
- <u>Crop Rotation:</u> This involves planting crops with high residue (e.g corn, small grains, e.t.c) in rotation,as the layer of residue would protect the topsoil.
- <u>Built in structural diversion</u> : Used often for gully control, to regulate flow of water away from the field and through designated desired paths.
- <u>Conservation Tillage</u>: This involves methods such as no-till planting, strip rotary tillage, etc, which do not allow the soil surface to be smooth and bare, but instead covered with crop residue that protects the soil from eroding forces.
Alkaline Earth Metals are the elements located in the second period from the left of the periodic table. These elements lose two electrons to form the stable octet when forming an ionic bond, resulting in a net charge of +2. Because they’re trying to get rid of those electrons to get to the stable octet, it’s easy to remove them - this means that the ionization energy of these elements is relatively low. Finally, since they’re looking to get rid of electrons, they certainly aren’t trying to gain any, meaning that their electronegativity is relatively low.
The correct answers are A and D.
Answer:
Explanation:
When a salt is dissolved , it increases the boiling point . Increase in boiling point depends upon number of ions . So it is a colligative property .
.19 m AgNO₃ . Each molecule will ionize into two ions . So effective molar concentration is 0.19 x 2 = .38 m
0.17 m CrSO4.Each molecule will ionize into two ions . So effective molar concentration is 0.17 x 2 = .34 m
0.13 m Mn(NO₃)₂. Each molecule will ionize into three ions . So effective molar concentration is 0.13 x 3 = .39 m
0.31 m Sucrose(nonelectrolyte). Molecules will not ionize . So effective molar concentration is 0.31 x 1 = .31 m
Higher the molar concentration , greater the depression in boiling point .
So lowest boiling point is 0.13 m Mn(NO₃)₂.
second highest boiling point is 0.19 m AgNO3.
Third lowest boiling point is 0.17 m CrSO4
Highest boiling point or lowest depression 0.31 m Sucrose.
a . 4
b . 1
c . 2
d . 3
The elements in a periodic table are arranged in the increasing order of their atomic number.
The question is missing the molecules in which the integration ratio of 2:3 will be observed. The complete question is given in the attachment.
Answer:
Molecule (a), (c), and (f) will show two peaks with the integration ratio of 2:3 in their 1H NMR spectrum
Explanation:
In the 1H NMR spectrum, the peak area is dependent on the number of hydrogen in a specific chemical environment. Hence, the ratio of the integration of these signals provides us with the relative number of hydrogen in two peaks. This rationale is used for the assignment of molecules that will give 2:3 integration ratio in the given problem.
- Molecule (a) have two CH₂ and three CH₃ groups. Hence, it will give two peaks and their integration ratio becomes 2:3 (Answer)
- Molecule (b) contains three chemical environments for its hydrogen atoms
- Molecule (c) have a single CH₂ and CH₃ group giving integration ratio of 2:3 (Answer)
- Molecule (d) will give two peaks but their ratio will be 1:3 because of two hydrogens of CH₂ and six hydrogens from two CH₃ groups
- Molecule (e) have three CH and three CH₃ groups, so their ratio will become 1:3
- Molecule (f) contains four CH and two CH₃ groups, giving two peaks. So, the integration ratio of their peaks is 2:3 (Answer)
- Molecules
- (g)
- and
- (h)
- both have two CH and two CH₃ groups giving two peaks with the integration ratio of 1:3