Answer:
A. (CH3)3C-I reacts by SN1 mechanism whose rate is independent of nucleophile reactivity.
Explanation:
We must recall that (CH3)3C-I is a tertiary alkyl halide. Tertiary alkyl halides preferentially undergo substitution reaction via SN1 mechanism.
In SN1 mechanism, the rate of reaction depends solely on the concentration of the alkyl halide (unimolecular mechanism) and is independent of the concentration of the nucleophile. As a result of this, both Br^- and Cl^- react at the same rate.
That depends. there are 2 possible answers.
H
C - C = C - H gives a different answer on the right than on the left.
One the left side, the second Carbon is attached to a double bond and has but one hydrogen attached to it.
The Carbon on the right of the double bond has 2
H
C- C = C - H
H
I'm not sure what you should put. It's one of those things that I would repeat my argument and submit it.
112.2 milliliters volume of water will drip into the bucket in 44 minutes.
<h3>What is volume?</h3>
How much space an object or substance takes up. • Measured in cubic meters (m3), liters (L) & milliliters (mL).
Total drop = Drops per minute X time
= 51 drops per minute X 44 minutes
=2244 drop
Volume of water will drip into the bucket in 44 minutes
=Total drop X Volume of each drop
=0.050 milliliters X 2244 drop
=112.2 milliliters
Hence, 112.2 milliliters volume of water will drip into the bucket in 44 minutes.
Learn more about volume here:
brainly.com/question/10904074
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Explanation:
- It is known that the amount of heat necessary to raise the temperature of 1 gram of a substance by
is known as specific heat.
Since, q = 
So, larger is the specific heat of a substance less will be the change in its temperature.
Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.
- Similarly, the specific heat of gold is lesser than the given materials or metals. Hence, gold will requires less heat to rise its temperature.
As a result, water present in gold will heat readily.
- As the relation between heat and specific heat is as follows.
q =
Therefore, calculate the amount of heat required by the water as follows.
q =
= 
= 33440 J
or, = 33.44 kJ (as 1 kJ = 1000 J)
Thus, 33.44 kJ heat would it take to raise the temperature of 100.0 g of water from 
to 
.
