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4 years ago

Can someone please help me find the arc length ?

Mathematics

1 answer:

Scorpion4ik [409]4 years ago

8 0

80 x 8.164653.12
653.12/360 = 1.814

arc length = 1.814 ( Round answer as needed)

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A year membership to Fun Zone costs $45 plus $1 per visit. A one-month membership costs $5 plus $3 per visit. Which multi-step e

Margaret [11]

Answer:

y = $45 + x

y = $5 + 3x

Step-by-step explanation:

The computation of the multi-step equations be shown below:

Let us assume the number of visits be x

So the first equation would be

y = $45 + x

And, the second equation would be

y = $5 + 3x

These are the multi-step equations with variable on the both sides

6 0

3 years ago

What is the true solution to 2 In eln 5x – 2 In 15?

babunello [35]

Answer:

x = 49.84

Step-by-step explanation:

We are given an equation of unknown x and we have to solve the equation for x.

$2\ln(e\ln5x)-2\ln15 =0$

⇒ $ln(e\ln5x) = \ln15$

⇒ $\ln e + \ln \ln 5x = \ln 15$ {Since we know that ln AB =ln A + ln B}

⇒ $\ln \ln 5x = \ln 15 -\ln e$

⇒ $\ln \ln 5x=\ln \frac{15}{e}$ {Since we know that ln A/B = ln A - ln B}

⇒ $\ln 5x = \frac{15}{e}$

⇒ $5x = e^{\frac{15}{e} }$

⇒ $x = \frac{1}{5} e^{\frac{15}{e} }$ {Converting logarithm to exponent form}

⇒ x = 49.84 (Approximate) (Answer)

6 0

4 years ago

a garden hose can 1/3 of a pool in 3/4 hour. How much of the pool can the garden hose fill in an hour?

mafiozo [28]

Answer:

20 is your whole answer.

Step-by-step explanation:

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5 0

3 years ago

Given: Elmwood St. and Oak Dr. are the same distance. All intersections are perpendicular.

vlabodo [156]

Answer:

The above result is proved with the help of Pythagoras theorem and explained below.

Step-by-step explanation:

Given figure ABCD in which AD=BC and all angles intersect at right angle. Hence, the triangle formed inside ADC and ABC are right angled triangle.

In triangle ADC,

By applying Pythagoras theorem, we get

$AC^{2}=AD^{2}+DC^{2}$ → (1)

In triangle ABC,

$AC^{2}=AB^{2}+BC^{2}$ → (2)

Now, from eq (1) and (2)

Peach Tree Dr. is the same distance as Sycamore Ln.

$AD^{2}+DC^{2} = AB^{2}+BC^{2}$

⇒ $DC^{2} = AB^{2}$ (∵ AD=BC)

⇒ DC=AB (∵Distance can never negative)

Therefore, Peach Tree Dr. is the same distance as Sycamore Ln.

8 0

3 years ago

Assuming that the population is normally distributed, construct a 9090% confidence interval for the population mean for each o

jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

Set B:

Mean: 4.5

Standard dev: 2.45

% = 90

Set A:

Standard Error, SE = s/ √n = 1.9/√8 = 0.67

Degrees of freedom = n - 1 = 8 -1 = 7

t- score = 1.89457861

Width of the confidence interval = t * SE = 1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width = 4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width = 4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

Set B:

Standard Error, SE = s/ √n = 2.45/√8 = 0.87

Degrees of freedom = n - 1 = 8 -1 = 7

t- Score = 1.89457861

Width of the confidence interval = t * SE = 1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width = 4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width = 4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.

6 0

4 years ago