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mote1985 [20]
3 years ago
12

A carbon atom and a hydrogen atom form what type of bond in a molecule?

Chemistry
1 answer:
Illusion [34]3 years ago
7 0
A carbon atom and a hydrogen atom would form a covalent bond in a molecule. Specifically it would be a Nonpolar covalent bond.
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You have 4 litres of a 3.0 mol/L solution of NaCl in a chemical store room.
ahrayia [7]

Answer:

12

Explanation:

nNaCl= 4x3=12

3 0
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How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
faltersainse [42]

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

  • Volume of the solution (V): 500 mL
  • Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

The molarity is the quotient between the moles of solute (n) and the liters of solution.

M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol

4 0
3 years ago
Why sometimes the electrons of an atom transfer to higher energy level​
Elenna [48]

Answer:

According to Bohr, the amount of energy needed to move an electron from one zone to another is a fixed, finite amount. ... The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level. This situation is unstable, however.

8 0
3 years ago
PLEASE HELP ME ASAP!!! <br> I need the answer to #9. If you can show work please do.
scoundrel [369]

The correct answer would be 32/16s


7 0
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Draw the major organic product in the reaction scheme below. Be sure to clearly show stereochemistry (if applicable).
Juliette [100K]

Answer:

see explanation below

Explanation:

You are missing the reaction scheme, but in picture 1, I found a question very similar to this, and after look into some other pages, I found the same scheme reaction, so I'm gonna work on this one, to show you how to solve it. Hopefully it will be the one you are asking.

According to the reaction scheme, in the first step we have NaNH2/NH3(l). This reactant is used to substract the most acidic hydrogen in the alkine there. In this case, it will substract the hydrogen from the carbon in the triple bond leaving something like this:

R: cyclopentane

R - C ≡ C (-)

Now, in the second step, this new product will experiment a SN2 reaction, and will attack to the CH3 - I forming another alkine as follow:

R - C ≡ C - CH3

Finally in the last step, Na in NH3 are reactants to promvove the hydrogenation of alkines. In this case, it will undergo hydrogenation in the triple bond and will form an alkene:

R - CH = CH - CH3

In picture 2, you have the reaction and mechanism.

6 0
3 years ago
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