Answer:
The final temperature at 1050 mmHg is 134.57 
or 407.57 Kelvin.
Explanation:
Initial temperature = T = 55 = 328 K
Initial pressure = P = 845 mmHg
Assuming final to be temperature to be T' Kelvin
Final Pressure = P' = 1050 mmHg
The final temperature is obtained by following relation at constant volume
The final temperature is 407.57 K
Answer:
As you cool a matter to absolute zero, their kinetic energy reduces significantly and the molecules slows down and begins to aggregate together. ... As heat is added, the molecules gain more kinetic energy. This shown in their increase motion. When heat is withdrawn, the particles slows down hope this helped
An intensive property does not change when you take away
some of the sample. The procedures that a student could use to examine the
intensive property of a rectangular block of wood are the hardness, color,
density and molecular weight.
What volume of 2.50 m lead ll nitrato
Answer:
136.63 °C
Explanation:
ΔTb=Tb solution - Tb pure
Where; Tb pure = 133.60°C
molar mass of solute = 121.14 g/mol
number of moles of solute; 52.2g/121.14 g/mol = 0.431 moles
molality = 0.431 moles/350 * 10^-3 = 1.23 molal
Then;
ΔTb = Kb * m * i
Kb = 2.46°C kg mol^-1
m = 1.23 molal
i = 1
ΔTb = 2.46 * 1.23 * 1
ΔTb = 3.03 °C
Hence;
Tb solution = ΔTb + Tb pure
Tb solution = 3.03 °C + 133.60°C
Tb solution = 136.63 °C
