If I remember correctly, you would have to heat the reaction beaker over a burner..
I apologize if I'm wrong
Answer:
64.17 Moles of Au
Explanation:
(atoms and particles are the same)
3.85 x 10 ^25 x (1 mol
/6.02 x 10^23)
3.85 / 6 = .64166
.6416 x 10^2 = 64.166
If you round up the answer you will get 64.17
64.17 moles of Au
Answer:
The value of the equilibrium constant for the reaction A ⇒ B is Kc = 1.72 × 10³.
The value of the equilibrium constant for the reaction B ⇒ A is K'c = 5.81 × 10⁻⁴.
Explanation:
For the reaction A ⇒ B, the equilibrium constant (Kc) is equal to the forward rate constant (kf) divided by the reverse rate constant (ki).
![Kc=\frac{kf}{ki} =\frac{1.60 \times 10^{2} s^{-1} }{ 9.30 \times 10^{-2} s^{-1}} =1.72 \times 10^{3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7Bkf%7D%7Bki%7D%20%3D%5Cfrac%7B1.60%20%5Ctimes%2010%5E%7B2%7D%20s%5E%7B-1%7D%20%20%20%7D%7B%209.30%20%5Ctimes%2010%5E%7B-2%7D%20s%5E%7B-1%7D%7D%20%3D1.72%20%5Ctimes%2010%5E%7B3%7D)
If we consider the inverse reaction B ⇒ A, its equilibrium constant (K'c) is the inverse of the forward reaction equilibrium constant.
![K'c=\frac{1}{Kc} =\frac{1}{1.72 \times 10^{3} } =5.81 \times 10^{-4}](https://tex.z-dn.net/?f=K%27c%3D%5Cfrac%7B1%7D%7BKc%7D%20%3D%5Cfrac%7B1%7D%7B1.72%20%5Ctimes%2010%5E%7B3%7D%20%20%7D%20%3D5.81%20%5Ctimes%2010%5E%7B-4%7D)