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steposvetlana [31]
2 years ago
12

Guys can you help me please it’s due today

Chemistry
2 answers:
Sonja [21]2 years ago
8 0

Answer:

i hope it will help you ..

Stells [14]2 years ago
8 0
Good idea lol but yeah I’m walking back from work when we are back home
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Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is
Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal =  C_{134}H_{96}O_{9}NS

Molecular mass of coal = (134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm

Let’s calculate the mass of nitrogen in coal

Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}

Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = 4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0
2 years ago
Read 2 more answers
The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O represents an acid-base tritration. The equivalence point occurs when 24.75 mL o
artcher [175]
            moles NaOH = c · V = 0.2432 mmol/mL · 24.75 mL = 6.0192 mmol
            moles H2SO4 = 6.0192 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.0096 mmol
Hence
            [H2SO4]= n/V = 3.0096 mmol / 38.94 mL = 0.07729 M
The answer to this question is  [H2SO4] = 0.07729 M

6 0
2 years ago
Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
3 years ago
Could an organism survive without its mitochondria if all the other organelle were present
lisov135 [29]
No, <span>mitochondria convert the sugar, can give it(the cell) Nutrients (food) to mainly keep it fresh and alive. Without cells mitochondria can't do its job.</span>
8 0
3 years ago
Read 2 more answers
What is the molar concentration of the acid if 35.18 mL of hydrochloric acid was required to neutralize 0.745 g of ALUMINUM hydr
Makovka662 [10]

The mass number of aluminium hydroxide is 78 thus, the number of moles in 0.745 g is:

no. of moles= mass/ RFM

= 0.745/78

=0.00955moles

Therefore the 0.00955 moles should be in the 35.18 ml

therefore 1000ml of the solution will have:

(0.00955ml×1000ml)/35.18

=0.2715moles

The  solution will be 0.27M hydrochloric acid  

3 0
2 years ago
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