1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gelneren [198K]
4 years ago
6

A supersonic jet flying at 150 m/s is accelerated uniformly at the rate of 22m/s² for 20s.What is its final velocity

Physics
1 answer:
frozen [14]4 years ago
7 0
V=u+at where v is final velocity u is initial velocity a is acceleration and t is time taken

this v = 150+22 (20) =590 m/s
You might be interested in
A fast pitch softball player does a "windmill" pitch, moving her hand through a vertical circular arc to pitch a ball at 65 mph.
astraxan [27]

a) The centripetal acceleration is 1694 m/s^2

b) The force on the ball is 321.9 N

c) The direction of the force is upward

Explanation:

a)

The centripetal acceleration of an object in circular motion is given by

a=\frac{v^2}{r}

where

v is the speed of the object

r is the radius of the circle

In this problem, we have:

r = 50 cm = 0.50 m (the radius of the circle is equal to the distance between the shoulder and the ball)

v=65 mph \cdot \frac{1609 m/mi}{3600 s/h}=29.1 m/s is the speed

Substituting,

a=\frac{29.1^2}{0.50}=1694 m/s^2

b)

The force exerted by the hand on the ball is equal to the centripetal force, which is given by:

F=ma

where

m is the mass of the ball

a is the centripetal acceleration

In this problem, we have:

m = 0.19 kg

a=1694 m/s^2

Substituting, we find:

F=(0.19)(1694)=321.9 N

c)

In a uniform circular motion, the direction of the centripetal acceleration is always towards the centre of the circle.

As a result, since the  direction of the force is the same as the direction of the acceleration, the direction of the centripetal force is also towards the centre of the circle.

Therefore in this case, since the ball is at the lowest point in the circle, the  direction of the force is upward  (because it is towards the centre of the circular trajectory).

Learn more about centripetal force and acceleration:

brainly.com/question/2562955

#LearnwithBrainly

4 0
4 years ago
Materials in which electric charges move freely such as copper and aluminum are called
yuradex [85]

Answer:

Conductors allow electric charges to move freely

8 0
4 years ago
Gayle runs at a speed of 3.85 m/s and dives on a sled, initially at rest on the top of a frictionless snow-covered hill. After s
enot [183]

Answer:

Final velocity at the bottom of hill is 15.56 m/s.

Explanation:

The given problem can be divided into four parts:

1. Use conservation of momentum to determine the speed of the combined mass (Gayle and sled)

From the law of conservation of momentum (perfectly inelastic collision), the combined velocity is given as:  

p_i = p_f  

m_1u_1 + m_2v_2 = (m_1 + m_2)v

v = \frac{(m_1u_1 + m_2v_2)}{(m_1 + m_2)}

v=\frac{[50.0\ kg)(3.85\ m/s) + 0]}{(50.0\ kg + 5.00\ kg)}= 3.5\ m/s  

2. Use conservation of energy to determine the speed after traveling a vertical height of 5 m.

The velocity of Gayle and sled at the instant her brother jumps on is found from the law of conservation of energy:  

E(i) = E(f)  

KE(i) + PE(i) = KE(f) + PE(f)  

0.5mv^2(i) + mgh(i) = 0.5mv^2(f) + mgh(f)  

v(f) = \sqrt{[v^2(i) + 2g(h(i) - h(f))]}

Here, initial velocity is the final velocity from the first stage. Therefore:  

v(f) = \sqrt{[(3.5)^2+2(9.8)(5.00-0)]}= 10.5\ m/s

3. Use conservation of momentum to find the combined speed of Gayle and her brother.  

Given:

Initial velocity of Gayle and sled is, u_1(i)=10.5 m/s

Initial velocity of her brother is, u_2(i)=0 m/s

Mass of Gayle and sled is, m_1=55.0 kg

Mass of her brother is, m_2=30.0 kg

Final combined velocity is given as:

v(f) = \frac{[m_1u_1(i) + m_2u_2(i)]}{(m_1 + m_2)}  

v(f)=\frac{[(55.0)(10.5) + 0]}{(55.0+30.0)}= 6.79 m/s  

4. Finally, use conservation of energy to determine the final speed at the bottom of the hill.

Using conservation of energy, the final velocity at the bottom of the hill is:  

E(i) = E(f)  

KE(i) + PE(i) = KE(f) + PE(f)  

0.5mv^2(i) + mgh(i) = 0.5mv^2(f) + mgh(f)  

v(f) = \sqrt{[v^2(i) + 2g(h(i) - h(f))]} \\v(f)=\sqrt{[(6.79)^2 + 2(9.8)(15 - 5.00)]}\\v(f)= 15.56\ m/s

6 0
3 years ago
This gradual change in beak size over time is known as _______.
yan [13]
The correct answer is evolution
4 0
4 years ago
Read 2 more answers
Can somebody please answer this correctly I will give brainliest
vodka [1.7K]
I think what’s wrong is that the paper clip isn’t connecting to the other thing on the bottom
8 0
3 years ago
Other questions:
  • Jeff puts on a leather jacket over his sweater. The sweater becomes negatively charged. Which statements about Jeff’s situation
    13·2 answers
  • A dragster with a mass of 700 kg attains a speed of 120 m/s in the quarter mile. Immediately after passing the timing lights, th
    5·1 answer
  • Convert 60 miles/hour to m/s (1.6km = 1mile; 1000m = 1km)
    8·1 answer
  • You run 100 m in 15 seconds. What is your speed in m/s
    13·1 answer
  • Which is an example of transformation potential energy to kinetic energy? Select two.
    14·2 answers
  • Infer how distance and speed in the motions of a clock parts are used to measure time
    8·1 answer
  • Please help, it's super easy!
    5·2 answers
  • As part of an advanced lab project, you design and construct a solenoid by wrapping a single layer of copper wire with a thin la
    10·1 answer
  • An autographed baseball rolls off of a 0.93 m high desk and strikes the floor 0.56 m away from the desk. How fast was it rolling
    12·1 answer
  • What is alpha particle, beta particle and gamma rays​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!