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Gelneren [198K]
4 years ago
6

A supersonic jet flying at 150 m/s is accelerated uniformly at the rate of 22m/s² for 20s.What is its final velocity

Physics
1 answer:
frozen [14]4 years ago
7 0
V=u+at where v is final velocity u is initial velocity a is acceleration and t is time taken

this v = 150+22 (20) =590 m/s
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Answer:

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Explanation:

The electric field strength can be found out disk with a uniform positive surface charge density by

E= (\sigma/\2epsilon_o)(1-z/ \sqrt(z^2+r^2))

σ= charge density

r= radius of the disk

z= position in which we have to find electric field = 15 cm

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putting values we get

E= \frac{2.5\times10^{-6}}{2\times2.5\times10^{-6}}(1-\frac{0.15}{\sqrt{0.15^2+0.075^2} })

solving we get

E=30000 N/c

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