An automobile with a mass of 1450 kg is parked on a moving flatbed railcar; the flatbed is 1.50 m above the ground. The railcar
1 answer:
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Answer:
Explanation:
The work of force 2 will be given by the vectorial equation . We know the value of
and have information about its movement, which relates to the net force
.
About this movement we can obtain the acceleration using the equation . Since it departs from rest we have
.
And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have
And we had the work done by force 2 as:
(The sign will be given algebraically since we take positive the direction to the right.)
With our values:
<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>
<em></em>
<em>Which leads us to the previous equation straightforwardly.</em>
Answer:
T= 8.061N*m
Explanation:
The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:
T = Fr
where F is the force, r the radius.
if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.
Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:
r =
r = 0.5374m
Finally, replacing the value of r and F, we get that the maximun torque is:
T = 15N(0.5374m)
T= 8.061N*m