Answer:
v₁ = 4 [m/s].
Explanation:
This problem can be solved by using the principle of conservation of linear momentum. Where momentum is preserved before and after the missile is fired.

where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]

where:
m₁ = mass of the tank = 500 [kg]
v₁ = velocity of the tank after firing the missile [m/s]
m₂ = mass of the missile = 20 [kg]
v₂ = velocity of the missile after firing = 100 [m/s]
![(500*v_{1})=(20*100)\\v_{1}=2000/500\\v_{1}=4[m/s]](https://tex.z-dn.net/?f=%28500%2Av_%7B1%7D%29%3D%2820%2A100%29%5C%5Cv_%7B1%7D%3D2000%2F500%5C%5Cv_%7B1%7D%3D4%5Bm%2Fs%5D)
The correct choices, sequentially and respectively, are c., d., d., a., d.
Answer:
1.974 g
Explanation:
Electrochemical equivalent of copper, z = 0.000329 g/C
I = 10 A
t = 10 minutes = 10 x 60 = 600 seconds
By the use of Farady's law of electrolysis
m = z I t
m = 0.000329 x 10 x 600
m = 1.974 g
Answer:
it's B I think I did this the other day tbh sorry if it's wrong btw hope this helps
Well you first need an equation, then put it on a graph