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Svetach [21]
3 years ago
8

A gaseous sample of nitrogen contains 2.41 grams (0.086 mol). What volume does this mixture occupy at 28 °C and 1.05 atm of pres

sure? Hint = Be sure to convert to Kelvin first!
0.19 L

0.38 L

1.8 L

2.0 L

4.0 L
Chemistry
1 answer:
denis23 [38]3 years ago
4 0

Answer:

2.20L

Explanation:

Number of moles = 0.086moles

Volume = ?

Temperature (T) = 28°C = (28 + 273.15)K = 301.15K

Pressure = 1.05atm

R = 0.082J/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the gas

V = volume

n = number of moles of the gas

R = ideal gas constant

T = temperature of the gas

PV = nRT

V = nRT / P

V = (0.086 × 0.082 × 301.15) / 1.05

V = 2.123 / 1.05

V = 2.02L

Volume of the gas is 2.02L

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5 0
3 years ago
A gas at 400 k is placed in a 4.0 l moveable piston. The gas is cooled to 252 k. What is the new volume of the piston?
katrin [286]

Answer:

2.52L

       

Explanation:

Given parameters:

T₁  = 400K

V₁  = 4L

T₂ = 252K

unknown

V₂ = ?

Solution:

To solve this problem, we are going to apply charle's law. The law states that the volume of a fixed mass of gas is directly proportional to temperature provided pressure is constant.

Mathematically,

               \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

Substitute and solve for V₂

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6 0
3 years ago
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