A gaseous sample of nitrogen contains 2.41 grams (0.086 mol). What volume does this mixture occupy at 28 °C and 1.05 atm of pres
sure? Hint = Be sure to convert to Kelvin first!
0.19 L
0.38 L
1.8 L
2.0 L
4.0 L
1 answer:
Answer:
2.20L
Explanation:
Number of moles = 0.086moles
Volume = ?
Temperature (T) = 28°C = (28 + 273.15)K = 301.15K
Pressure = 1.05atm
R = 0.082J/mol.K
From ideal gas equation,
PV = nRT
P = pressure of the gas
V = volume
n = number of moles of the gas
R = ideal gas constant
T = temperature of the gas
PV = nRT
V = nRT / P
V = (0.086 × 0.082 × 301.15) / 1.05
V = 2.123 / 1.05
V = 2.02L
Volume of the gas is 2.02L
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