Answer:
Option 1 is correct. C10H10N10O2
Explanation:
Step 1: Data given
Mass of a compound = 8.84 grams
Mass of C = 3.53 grams
Mass of H = 0.295 grams
Mass of N = 4.08 grams
Mass of O = 0.935 grams
Atomic mass C = 12.01 g/mol
Atomic mass H = 1.01 g/mol
Atomic mass N = 14.0 g/mol
Atomic mass O = 16.0 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles C = 3.53 grams / 12.01 g/mol
Moles C = 0.294 moles
Moles H = 0.295 grams / 1.01 g/mol
Moles H = 0.292 moles
Moles N = 4.08 grams / 14.0 g/mol
Moles N = 0.291 moles
Moles O = 0.935 grams / 16 g/mol
Moles O = 0.0584 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 0.294 / 0.0584 = 5
H: 0.292 / 0.0584 = 5
N: 0.291/0.0584 = 5
O: 0.0584/0.0584 = 1
The empirical formula is C5H5N5O
Option 1 has this empirical formula
C10H10N10O2
