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torisob [31]
4 years ago
6

A stone is held at a height h above the ground. A second stone with four times the mass of the first one is held at the same hei

ght. The gravitational potential energy of the second stone compared to that of the first stone is
Physics
1 answer:
QveST [7]4 years ago
5 0

gravitational potential energy is given by formula

U = mgh

here we need to compare the gravitational potential energy of stone 2 with respect to stone 1

so we will say

\frac{U_2}{U_1} = \frac{m_2gh}{m_1gh}

\frac{U_2}{U_1} =\frac{m_2}{m_1}

given that

m_2 = 4 m_1

now we have

\frac{U_2}{U_1} = 4

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A baseball is thrown with an initial velocity of 45.4 m/s at an angle of 31.2 ∘ .
sveticcg [70]

Answer:

V (initial vertical velocity) = 45.4 sin 31.2 = 23.52 m/s

1/2 m V^2 = m g h      conservation of energy

h = V^2 / (2 g) = 23.52^2 / 19.6 = 28.2 m       max height

Check:

t = 28.2 / 9.8 = 2.88 sec    time to reach max height

h = 23.52 * 2.88 - 1/2 g 2.88^2 = 27.1 m

8 0
2 years ago
Optics of the eye: the closest object that a typical young person with normal vision can focus on clearly is closest to:______.
Natali [406]

The human eye is one of the most valuable sense organ. The closest object that a typical young person with normal vision can focus closest to is 25 cm

The lens in the eye forms the image on the retina. The image formed is real and inverted. The retina is a very delicate membrane containing numerous light sensitive cells.

This light sensitive cells gets activated when light falls on it and generates electric signals. These electric signals are sent to the brain via the optic nerves present in the eye. The brain finally processes these signals and thus we see the object clearly.

The ability of the lens of the eye to adjust its focal length accordingly is called the power of accommodation,

The minimum distance, at which the object can be seen clearly without any strain is called the least distance of distinct vision.

To see an object clearly without any strain is when we place it at about 25 cm from the eye.

Tolearn more about optics of the eye : brainly.com/question/22371574

#SPJ4

5 0
2 years ago
What moves electrons in a circuit?
erik [133]
I think it’s will be B
8 0
3 years ago
A mail carrier leaves the post office and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00
Oxana [17]

Answer:

12.97 km

Explanation:

In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.

Taking north as positive y direction and east as positive x-direction, we have:

- Displacement 1: 2.00 km to the north

So

A_x = 0\\A_y = +2.00 km

- Displacement 2: 60.0° south of east for 7.00 km

So

B_x=(7.00)(cos (-45^{\circ}))=4.95 km\\B_y = (7.00)(sin (-45^{\circ}))=-4.95 km

- Displacement 3: 9.50 km 35.0° north of east

So

C_x=(9.50)(cos 35^{\circ})=7.78 km\\C_y=(9.50)(sin 35^{\circ})=5.45 km

So the net displacement along the two directions is:

R_x=A_x+B_x+C_x=0+4.95+7.78=12.73 km\\R_y=A_y+B_y+C_y=2.00+(-4.95)+5.45=2.50 km

So, the  distance between the initial and final position is equal to the magnitude of the net displacement:

R=\sqrt{R_x^2+R_y^2}=\sqrt{12.73^2+2.50^2}=12.97 km

7 0
3 years ago
A car's acceleration is 3m/s2. If the car started at rest and it only took 10s for the car to reach this acceleration, what is t
Grace [21]

Answer:

30m/s

Explanation:

From law of motion equation

Vf= Vi + at

Where Vf= final velocity

Vi= initial velocity=0(the car started at rest)

a= acceleration= 3m/s2

t= time= 10s

Then substitute into the equation to get the final velocity.

Vf= 0+(10×3)

Vf= 30m/s

Hence, the car's final velocity is 30m/s

5 0
3 years ago
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