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Vedmedyk [2.9K]
3 years ago
15

Which trophic level usually has the LEAST energy available to it?

Physics
1 answer:
DerKrebs [107]3 years ago
3 0
The TERTIARY CONSUMER has the least energy available to it.
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A storm cloud has a charge of 0.055 C. Due to polarization, the top of a tree gains a charge of -0.006 C. The cloud moves to 98
Anastasy [175]

Answer:

F = 309.24 N

Explanation:

Given that,

Charge on a strom cloud, q₁ = 0.055 C

The charge gained by the top of a tree, q₂ = -0.006 C

The cloud moves to 98 meters above the tree.

We need to find the amount of force between the cloud and the tree. The electrical force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 0.055\times 0.006 }{(98)^2}\\\\F=309.24\ N

So, the force between the cloud and the tree is equal to 309.24 N.

5 0
3 years ago
The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2 gas. Which co
svp [43]

Answer:

2 in front of water and 1 in front of oxygen

Explanation:

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3 years ago
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What layer forms the largest portion of Earth
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The earth is made up of 3 layers,the crust,mantle,and core,but the largest is the mantle
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Let's say you are on the third story of an apartment building that has a swimming pool. For some insane reason you think it is a
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To make it into the pool you must run and jump at

\displaystyle v_o=x.\sqrt{\frac{g}{2y}}

Explanation:

Horizontal Launch

When an object is thrown with a specified initial speed in the horizontal direction, it describes a curved path that finishes when it hits the ground level after traveling certain horizontal distance x and a vertical height y from the launching point. The horizontal speed is always constant and the vertical speed increases due to the effect of gravity. It can be found that the horizontal distance reached by the object when launched at an initial speed  in a given time t is

x=v_o.t

And the vertical distance is

\displaystyle y=\frac{g.t^2}{2}

If t is the total flight time, then x and y are maximum and we can find a relation between them. Solving for t in the first equation

\displaystyle t=\frac{x}{v_o}

Substituting in the second equation

\displaystyle y=\frac{g}{2}\left ( \frac{x}{v_o}\right )^2

Rearranging

\displaystyle \left ( \frac{v_o}{x}\right )^2=\frac{g}{2y}

Solving for v_o

\displaystyle v_o=x.\sqrt{\frac{g}{2y}}

There are many applications for the horizontal launch. One common situation is when someone wants to drop something on certain terrain at a specific approximate point when traveling in a plane at a given height. Once the object is left fall, it has the same speed as the plane, so the plane speed can be estimated to make the best possible launch, or given that speed, we can know in advance where the object will reach ground level

4 0
3 years ago
A person travels 1.5 km in 6 minutes, how fast were they traveling in meters per second?
Evgen [1.6K]

Answer:

4.167m/sec

Explanation:

1km=1000m

1.5km=1500m

1min=60sec

6min=360sec

In 360sec they travel 1500m

In 1 sec they travel=1500m/360

1sec=4.167m

7 0
3 years ago
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