Question

A toroid of mean radius 26 cm and circular cross section of radius 1.9 cm is wound with a superconducting wire of length 1000 m that carries a current of 410 A. (a) What is the number of turns on the coil?

Answer 1

Answer:

8377 turns

Explanation:

Given:

Mean radius of toroid = 26 cm

Circular cross-section radius, r = 1.9 cm = 0.019

Length of the wire, l = 1000 m

The number of turns (n) on the coil is given by  

$n = \frac{l}{s}$

where,

l is the length of the wire

s is the circumference of the circular wire

⇒$n = \frac{1000}{2\pi r}$

or

$n = \frac{1000}{2\pi \times 0.019}$

or

n = 8376.57 or 8377 turns

hence, the number of turns on the coils is 8377