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Gelneren [198K]
3 years ago
15

Ionic compounds can conduct electricity when dissovled in water or mellted , becasue

Chemistry
1 answer:
nata0808 [166]3 years ago
8 0
Because the ions forming the compound will have to separate from each other then. As a result, ionic compounds disintigrated into a myriad of single lonely ions floating free in water (in solutions). The process is known as electrolytic dissociation.

Eletric current is co-directed movement of particles exhibiting similar charge.

Water doesn't have charged particles constituting it. No electricity.

Ionic compounds do have charged particles (i.e. ions), but those are locked within the lattice and cannot move. No electricity.

Ionic compounds in water disintegrate into free floating (capable of moving) ions (charged particles). All you have to do is get all the positive charges moving one way and all the negative ones moving the other and here you have it - electricity! That is achieved through applying external magnetic field.

This is why ionic compunds can conduct electricity when dissolved in water or melted.
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A group of students collects data to determine whether compounds were ionic or covalent. They placed each compound in a small bo
yan [13]

Answer:

the answer is B.  

No, as ionic compounds are only conductive in an aqueous (water) solution

Explanation: i just know

8 0
3 years ago
PLEASE HELP ASAP !!
Ivenika [448]

Answer:

  • 2SO₂ +  O₂ + 2H₂O  -----------> 2H₂SO₄
  • Theoretical yield of H₂SO₄ = 213 g
  • percent yield of H₂SO₄ = 94 %  

Explanation:

Data Given:

volume of SO₂ = 48.6 L

mass of H₂SO₄ = 200 g

balance equation = ?

theoretical yield = ?

percent yield = ?

Solution:

Part 1:

first we have to write a balance equation for the reaction

SO₂ gas react with water (H₂O) and excess oxygen

The balanced equation is as under

                       2SO₂ +  O₂ + 2H₂O  -----------> 2H₂SO₄

Part 2:

Now we have to find theoretical yield

First look at the balance reaction

                        2SO₂ +  O₂ + 2H₂O  -----------> 2H₂SO₄

                        2 mol                                         2 mol

2 moles of SO₂ give gives 2 moles of H₂SO₄

Now calculate volume of 2 moles of SO₂ and mass of 2 moles of H₂SO₄

volume of 2 moles of SO₂

Formula used

                 volume of gas = no. of moles x molar volume . . . . . . (1)

molar volume of SO₂= 22.4 L/mol

Put values in above formula (1)

                 volume of gas = 2 mol x 22.4 L/mol

                 volume of gas = 44.8 L

volume of 2 mole of SO₂ = 44.8 L

Now,

Find mass of 2 mole H₂SO₄

Formula Used

            mass in grams = no. of moles x molar mass . . . . . . . (2)

molar mass of H₂SO₄ = 2 (1) + 32 + 4(16)

molar mass of H₂SO₄ = 98 g/mol

put values in equation 2

        mass in grams = 2 mol x 98 g/mol

        mass in grams = 196 g

mass of 2 mole of H₂SO₄ = 196 g

** So,

Now we come to know that

44.8 L of SO₂ gives 196 g of H₂SO₄ then how many grams of the H₂SO₄ will be produced by 48.6 L of SO₂

Apply unity Formula

               44.8 L of SO₂ ≅ 196 g of H₂SO₄

               48.6 L of SO₂ ≅ X g of H₂SO₄

Do cross multiplication

                g of H₂SO₄  = 196 g x 48.6 L / 44.8 L

                g of H₂SO₄  =  213 g

So that is why the theoretical yield of H₂SO₄ is 213 g

Theoretical yield of H₂SO₄ = 213 g

Part 3

Calculate Percent Yield:

Formula used for this purpose:

             percent yield = actual yield /theoretical yield x 100 %

Put value in the above formula

           percent yield = 200 g/ 213 g x 100 %

          percent yield = 94 %    

So percent yield of H₂SO₄ = 94 %    

8 0
3 years ago
Assign an oxidation number to each atom in the products.
Rzqust [24]
<h3>Answer:</h3>

Oxidation number refers to a number given to an atom which shows the number of number of electrons lost (or gained, if the number is negative), by an atom of that element in the compound.

Hence oxidation number of following atoms in given reaction are:

In NaOH:

Na = +1

O = -2

H = +1

In H2:

H = 0


8 0
3 years ago
Read 2 more answers
6 NaOH + 2 Al ???? 2 Na3AlO3 + 3 H2 How much aluminum is required to produce 17.5 grams of hydrogen? How many moles of NaOH are
ANTONII [103]

Answer:

a) 157.5 grams of aluminum.

b) 1 mol

c) 9 g

Explanation:

The reaction is :

6 NaOH + 2Al ---> 2 Na_{3}AlO_{3} + 3H_{2}

As per balanced equation

a) 3 moles of hydrogen will be produced from two moles of aluminium.

The atomic mass of aluminium = 27

therefore

3X2 grams of hydrogen is produced from 2 X 27 grams of Al

1 gram of hydrogen will be produced from \frac{2X27}{3X2}= 9g

therefore 17.5 will be produced from = 9X 17.5 = 157.5 grams of aluminum.

b) as per balanced equation three moles or six gram of hydrogen is produced from 6 moles of NaOH.

Therefore 1 g of hydrogen will be produced from =\frac{6}{6}

or 1 gram will be prepared from = 1 mole

c) from balanced equation three moles are produced from two moles of Al (27X2 = 54 g).

thus from 54  grams gives 6 grams of hydrogen

1 grams will give = \frac{54X1}{6}= 9 g

7 0
3 years ago
Read 2 more answers
Example of a homoatomic and heteroatomic molecule
il63 [147K]

Answer:

Some examples of homoatomic molecules are hydrogen gas, and oxygen gas and some examples of heteroatomic molecules are water, methane

Explanation:

3 0
3 years ago
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