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3 years ago

I WILL RATE BRAINLIEST! I JUST NEED HELP!

2 answers:

6 0

If they're half life, wouldn't that mean every 5730 years I would double? So 12.5 x 2= 25, 25 x 2 = 50, and 50 x 2 = 100% carbon-14. It doubled 3x so the 5730 x 3 = amount of years the volcano erupted

ycow [4]3 years ago

5 0

It erupted 17,190 years ago.
It has a half life of 5,730 years. Therefore, when it has 50% remaining, it has lived for 5,730 years. When it has 25% remaining, it has lived for 11,460 (5730+5730). When it has 12.5% remaining (25/2), then it has lived 17,190 years (11,460 + 5730).
:D

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What is the percent composition by mass of hydrogen in nh4hco3

Simora [160]

Answer: The percent composition by mass of hydrogen in given compound is 6.33 %

Explanation:

We are given:

A chemical compound having chemical formula of $NH_4HCO_3$

It is made up by the combination of 1 nitrogen atom, 5 hydrogen atoms, 1 carbon atom and 3 oxygen atoms

To calculate the percentage composition by mass of hydrogen in the compound, we use the equation:

$\%\text{ composition of Hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100$

Mass of compound = $[(1\times 14)+(5\times 1)+(1\times 12)+(3\times 16)]=79g/mol$

Mass of hydrogen = $(5\times 1)=5g/mol$

Putting values in above equation, we get:

$\%\text{ composition of Hydrogen}=\frac{5g/mol}{79g/mol}\times 100=6.33\%$

Hence, the percent composition by mass of hydrogen in given compound is 6.33 %

6 0

3 years ago

A 4.00g sample of helium has a volume of 24.4L at a temperature of 25.0oC and a pressure of 1.00 atm. The volume of the helium i

Masteriza [31]

Answer:

0.41 moles.

Explanation:

Given that:

Mass of helium = 4.00 g

Initial Volume = 24.4 L

initial Temperature = 25.0 °C =( 25 + 273) = 298 K

initial Pressure = 1.00 atm

The volume was reduced to :

i.e

final volume of the helium - 10.4 L

Change in ΔV = 24.4 - 10.4 = 10.0 L

Temperature and pressure remains constant.

The new quantity of gas can be calculated by using the ideal gas equation.

PV = nRT

n = $\frac{PV}{RT}$

n = $\frac{1.00*10.0}{0.082057*298}$

n = 0.4089 moles

n = 0.41 moles.

7 0

2 years ago

An atom has 13 protons, 13 neutrons, and 13 electrons. Another atom has 13 protons, 14 neutrons, and 13 electrons. Analyze and e

olga nikolaevna [1]

They are alike bc they both have 13 protons and neutrons

3 0

2 years ago

Robidium and cesium have similar chemical properties because in the ground it states the atoms of both elements each have

anzhelika [568]

It would be one electron in the outermost shell. Hope this helps!

5 0

2 years ago

Write the net ionic equation for ammonium carbonate and lead(II) nitrate are combined. (Use the solubility rules provided in the

sashaice [31]

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium carbonate and lead (II) nitrate is given as:

$(NH_4)_2CO_3(aq.)+Pb(NO_3)_2(aq.)\rightarrow 2NH_4NO_3(aq.)+PbCO_3(s)$

Ionic form of the above equation follows:

$2NH_4^{+}(aq.)+CO_3^{2-}(aq.)+Pb^{2+}(aq.)+2NO_3^{-}(aq.)\rightarrow PbCO_3(s)+2NH_4^+(aq.)+2NO_3^-(aq.)$

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Pb^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow PbCO_3(s)$

Hence, the net ionic equation is written above.

8 0

3 years ago