Answer:
Density,
Explanation:
It is given that the density of liquid mercury is 13.6 g/mL. We need to convert the density into lb/in³.
We know that,
2.205 lbs= 1 kg
1 g = 0.0022 lb
1 mL = 0.0610 in³
So, the density of liquid mercury is .
Answer: -
Group 5 - Metalliods.
Group 7 - Halogens Group
Group 8 - Noble Gases
Explanation: -
Group 1 are the alkali metals.
Group 2 are the alkaline earth metals.
Group 5 are a part of transition metals which range from Group 3 to Group 12.
Group 17 are the halogens.
Group 18 are the noble gases.
Answer:
1.44 atm
Explanation:
Step 1:
We'll begin by calculating the number of mole in 2,800,000 Liter of air.
I mole of air occupy 22.4L.
Therefore, Xmol of air will occupy 2800000L i.e
Xmol of air = 2800000/22.4
Xmol of air = 125000 moles
Step 2:
Determination of the pressure when the balloon is fully inflated .
This can be obtained as follow:
Number of mole (n) of air = 125000 moles
Volume (V) = 2800000 L
Temperature (T) = 120°C = 120°C + 273 = 393K
Gas constant (R) = 0.082atm.L/Kmol
Pressure (P) =.?
PV = nRT
Divide both side V
P= nRT/V
P= (125000x0.082x393) / 2800000
P = 1.44 atm
Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm