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3 years ago

For a reaction to be in equilibrium.... *

Chemistry

1 answer:

IrinaK [193]3 years ago

3 0

Answer: C) the rate of forward reaction is not equal to the rate of backward reaction. This should be the answer.

Explanation:

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A certain amount of gas is trapped in a nonrigid container at atmospheric pressure. If the container is cooled and the gas in th

Akimi4 [234]

Answer:

D. The volume of the container will decrease.

Explanation:

We apply here, the general gas law of ideal gases:

PV = nRT,

where, P is the pressure of the gas.

V is the volume of the container.

n is the no. of moles of the gas.

R is the general gas constant.

T is the temperature of the gas.

We are given that P is constant.

Also, n is constant as there is no added external gases.

T is decreased as the container is cooled.

So, the volume will change as the container is nonrigid.

V α T.

The volume is directly proportional to the temperature,

Thus, as the container is cooled, the T will decrease, and the volume of the container will decrease.

8 0

3 years ago

Why do you think the Na+ ion is smaller than a neutral Na atom? Why do you think the Cl - ion is larger than a neutral Cl atom?

Sphinxa [80]

Answer:

Na+ ion is smaller than a neutral Na atom in the ion there was one more proton which will attract electron bring it closer to the center making the atomic radius smaller. Therefore making a Na+ ion is smaller than a neutral Na atom Explanation:

yes

7 0

3 years ago

Help this is so confusing like

melamori03 [73]

zoom in a bit more thanks

5 0

3 years ago

Read 2 more answers

Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

7 0

3 years ago

To prepare the cooling system for an ice cream freezer, the chef adds 59.7 g of salt (NaCl) to 1433.3 g of ice. Predict the lowe

nordsb [41]

Answer: The entire water/ice solution is at the melting/freezing point, 32°F (0°C). Adding rock salt — or any substance that dissolves in water — disrupts this equilibrium.

Explanation: Hope this helps! Have a great day :)

7 0

3 years ago