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sammy [17]
3 years ago
9

Gaseous ethane, C2H6, burns in the presence of oxygen

Chemistry
1 answer:
Gnesinka [82]3 years ago
3 0

Moles of Carbon dioxide(CO2) = 2

<h3>Further explanation</h3>

Given

Reaction

2 C2H6 (g) + 7 O2 (g) —+ 4CO2 (g) + 6 H20 (g)

Required

moles of carbon dioxide

Solution

The reaction coefficient shows the mole ratio of the compounds in the reaction equation (reactants and products)

From the equation, mol ratio of C2H6 : CO2 = 2 : 4, so mol CO2 :

mol CO2 = (4/2) x mol  C2H6

mol CO2 = 2 x 1

mol CO2 = 2

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An unknown triprotic acid (H3A) is titrated with NaOH. After the titration Ka1 is determined to be 0.0053 and Ka2 is determined
Savatey [412]

Answer:

Ka3 for the triprotic acid is 7.69*10^-11

Explanation:

Step 1: Data given

Ka1 = 0.0053

Ka2 = 1.5 * 10^-7

pH at the second equivalence point = 8.469

Step 2: Calculate Ka3

pKa = -log (Ka2) = 6.824

The pH at the second equivalence point (8.469) will be the average of pKa2  and pKa3. So,

8.469 = (6.824 + pKa3) / 2

pKa3 = 10.114

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6 0
4 years ago
The burning of fossil fuels results in which type of chemical reaction
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5 0
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Vanadium has an atomic mass of 50.9415 amu. It has two common isotopes. One isotope has a mass of 50.9440 amu and a relative abu
grandymaker [24]

Answer:

Average atomic mass of the  vanadium = 50.9415 amu

Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975

Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu

Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025

Atomic mass of Isotope (II) of vanadium ,m' = ?

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Explanation:

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3 years ago
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3 years ago
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