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sammy [17]
3 years ago
9

Gaseous ethane, C2H6, burns in the presence of oxygen

Chemistry
1 answer:
Gnesinka [82]3 years ago
3 0

Moles of Carbon dioxide(CO2) = 2

<h3>Further explanation</h3>

Given

Reaction

2 C2H6 (g) + 7 O2 (g) —+ 4CO2 (g) + 6 H20 (g)

Required

moles of carbon dioxide

Solution

The reaction coefficient shows the mole ratio of the compounds in the reaction equation (reactants and products)

From the equation, mol ratio of C2H6 : CO2 = 2 : 4, so mol CO2 :

mol CO2 = (4/2) x mol  C2H6

mol CO2 = 2 x 1

mol CO2 = 2

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Answer:- No, the company would not be able to full fill the order.

Solution:- The balanced equation for the formation of ammonia by the reaction of hydrogen with nitrogen is:

3H_2+N_2\rightarrow 2NH_3

We have been given with 22000 grams of nitrogen and 1000 grams of hydrogen. Let's convert grams of each to moles:

moles of nitrogen = 22000g N_2(\frac{1mol}{28g})

moles of nitrogen = 785.71 mol

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From balanced equation 3 moles of hydrogen react with 1 mol of nitrogen. Let's calculate how many moles of nitrogen would react with 500 mol of hydrogen:

500mol H_2(\frac{1mol N_2}{3mol H_2})

= 166.67 mol N_2

166.67 moles of nitrogen are required and 785.71 moles of it are available. It means nitrogen is in excess and hydrogen is limiting. Product yield depends on limiting reactant. So, let's calculate the amount of ammonia formed from moles of hydrogen as:

500mol H_2(\frac{2mol NH_3}{3mol H_2})(\frac{17g NH_3}{1mol NH_3})

= 5666.67g of ammonia

let's convert the grams of ammonia to number of batches as:

5666.67g NH_3(\frac{1 batch}{175g NH_3})

= 32 batches

Company needs to make 70 batches of ammonia but from given amounts of hydrogen and nitrogen only 32 batches could be made. It means the company would not be able to full fill the order.

5 0
3 years ago
A student determines that a 9.8 g mixture of MgCl₂ (s) and NaNO3(s) contains 0.050 mol of
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6 0
2 years ago
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