1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
joja [24]
3 years ago
8

"The combustion of ethylene proceeds by the reaction C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(g) When the rate of disappearance of O2 i

s 0.23 M s-1, the rate of disappearance of C2H4 is ________ M s-1."
Chemistry
1 answer:
Julli [10]3 years ago
7 0

Answer:

The rate of  disappearance of C_2H_4 is 0.0766 M/s.

Explanation:

C_2H_4(g)+3O_2(g)\rightarrow 2CO_2(g)+2H_2O(g)

Rate of the reaction = R

R=-\frac{1}{1}\frac{d[C_2H_4]}{dt}=-\frac{1}{3}\frac{d[O_2]}{dt}

[te]R=\frac{1}{2}\frac{d[CO_2]}{dt}=\frac{1}{2}\frac{d[H_2O]}{dt}[/tex]

Rate of disappearance of O_2 =0.23 M/s

Rate of disappearance of O_2=3\times R

0.23 M/s=3\times R

R =0.07666 M/s

Rate of disappearance of C_2H_4=1\times R

\frac{d[C_2H_4]}{dt}=1\times 0.23 m/s=0.0766 M/s

The rate of  disappearance of C_2H_4 is 0.0766 M/s.

You might be interested in
A concentration cell is constructed using two Ni electrodes with Ni2+ concentrations of 1.0 M and 1.00 � 10�4 M in the two half-
Komok [63]

<u>Answer:</u> The cell potential of the cell is +0.118 V

<u>Explanation:</u>

The half reactions for the cell is:

<u>Oxidation half reaction (anode):</u>  Ni(s)\rightarrow Ni^{2+}+2e^-

<u>Reduction half reaction (cathode):</u>  Ni^{2+}+2e^-\rightarrow Ni(s)

In this case, the cathode and anode both are same. So, E^o_{cell} will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Ni^{2+}_{diluted}]}{[Ni^{2+}_{concentrated}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

[Ni^{2+}_{diluted}] = 1.00\times 10^{-4}M

[Ni^{2+}_{concentrated}] = 1.0 M

Putting values in above equation, we get:

E_{cell}=0-\frac{0.0592}{2}\log \frac{1.00\times 10^{-4}M}{1.0M}

E_{cell}=0.118V

Hence, the cell potential of the cell is +0.118 V

5 0
3 years ago
Physical properties of reactants: Physical properties of products: 12.
dolphi86 [110]

Answer: The reactants are baking soda and vinegar. Baking soda is a white powder, and vinegar is a clear liquid. The products of this reaction are carbon dioxide, water, and sodium acetate. Carbon dioxide is a colorless gas, water is a colorless liquid, and sodium acetate is a white crystalline powder.

A chemical change can be seen in how the molecular formulas of the products are different from the reactants, since the reactants have chemically changed into completely different molecules.

Hope this helps

6 0
3 years ago
How do atoms in molecules bond? <br> plz answer I will give brainliest
spin [16.1K]

Answer:

Via covalent bonds

Explanation:

Atoms in molecules are bonded together via covalent bonds. Covalent bonds are bonds that are formed by sharing of the valence electrons between two atoms.

The atoms can be of the same kind or of different kinds.

  • In most molecules, the two atoms are connected by sharing of their valence electrons.
  • This way, each atom can attain stability by becoming isoelectric with the nearest noble gas.
  • Some molecules are monoatomic, some are polyatomic.
5 0
3 years ago
Please help and match them
alina1380 [7]
The answers from top to bottom right to left are
3,1,2,4
7 0
2 years ago
You have 2.2 mol Xe and 2.0 mol F₂, but when you carry out the reaction you end up with only 0.25 mol XeF₄. What is the percent
alexira [117]

Answer:

The correct answer is 25 %

Explanation:

According to the chemical reaction:

Xe(g) + 2 F₂ (g) → XeF₄ (g)

1 mol of Xe(g) reacts with 2 mol of F₂(g), so the stoichiometric ratio os reactants is 2 mol F₂/mol Xe.

We have 2.2 mol Xe and 2.0 mol F₂, so the ratio is:

2.0 mol F₂/2.2 mol Xe = 0.909 mol F₂/mol Xe

The molar ratio of reactant we have is lower than the required, so F₂ is the limiting reactant.

By using the limiting reactant, we calculate the theoretical amount of product (XeF₄). For this, we know that 1 mol of XeF₄ is formed from 2 mol of F₂ (1 mol XeF₄/ 2 mol F₂), and we have 2.0 mol F₂:

2.0 mol F₂ x (1 mol XeF₄/ 2 mol F₂)= 1 mol XeF₄

If we only obtained 0.25 mol XeF₄, the percent yield of the experiment is:

Yield = experimental amount/theoretical amount x 100%

        = 0.25 mol XeF₄/ 1 mol XeF₄ x 100% = 25 %

8 0
3 years ago
Other questions:
  • Which type of molecule is shown below?
    9·2 answers
  • Which option is an example of a chemical property? Question options: reactivity color melting point density
    15·2 answers
  • Which of the following statements is incorrect? A. Molecular mass is expressed in atomic mass units. B. Formula mass compares th
    5·1 answer
  • Use your Cabbage pH Indicator Key to determine the pH of each. Enter the pH ranges into the data table.
    15·2 answers
  • How does trace evidence end up transferring to the crime scene, suspect, or victim? Discuss some of the ways that this might hap
    9·1 answer
  • Convert 3.2 ft^2 to square inches
    7·1 answer
  • Should I say sorry to a boy who was tryna steal my friends backpack as a joke and I was tryna kick his hand and I kicked his nos
    9·1 answer
  • What is the "major drawback" to using word equations?
    11·2 answers
  • (12pts) Separation of Copper(II) and Bismuth(III) Ions Procedure Number and Ion Test Reagent or Technique Evidence of Chemical C
    9·1 answer
  • What is the effect of scary movies on pulse rates<br><br> a. Independent<br> b. Dependent:
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!