M = moles of solute / liters of solution
2.00 M = x / 10.0 L
x = 20.0 mol
Suppose the molarity was listed as 2.0 M (two sig figs). How to display the answer? Like this:
20. mol
You just have to convert the mass of water into volume.
To do that you use the density of water, which is about 1.0 g/ ml
So, from the formula of density D = M / V, you get V = M / D
=> V = 2.49 * 10^7 grams / 1.0 g / ml = 2.49 * 10 ^ 7 ml
You can pass that to liters using the conversion factor 1000 ml = 1 l
2.49 * 10^7 ml * 1 l / 1000 ml = 2.49 * 10^4 l = 24,900 l
Answer: 24,900 l
Answer:
54 grams of H₂O
Explanation:
4NH₃ + 3O₂ → 2N₂ + 6H₂O
Ratio is 4:6.
Let's convert the mass of ammonia in moles
Mass / Molar mass = Mol
34 g / 17 g/m = 2 moles
If 4 moles of ammonia are needed to produce 6 mol of water
2 mol of NH₃ will produce ( 2 .6 )/4 = 3 moles
Molar mass water = 18 g/m
Mass = mol . molar mass → 3 m . 18 g/m = 54 grams
