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3 years ago

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Teresa bought 3boxes of chocolate each box has 9 pieces of chocolate inside teresa gave away 15 pieces of chocolate how many pie

ces of chocolate does she have left

2 answers:

lora16 [44]3 years ago

4 0

Hey There!

3×9=27
27-15=12
Teresa has 12 pieces of Chocolate left

Hope This Helps!!!!

Fofino [41]3 years ago

4 0

3 x 9 = 27
28 - 15 = 12
Therefore she has 12 pieces of chocolate left.

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A regular octagonal pyramid. Each side of the base is 6 cm long. it has a height of 10cm. Find the surface area of the pyramid

attashe74 [19]

9514 1404 393

Answer:

470.16 cm²

Step-by-step explanation:

The apothem of the base is used for two purposes: to find the area of the base, and to find the slant height of each face.

The apothem of the base for side length s is ...

s/2 = a·tan(π/8)

a = s/(2·tan(π/8)) ≈ 7.24 cm

The slant height of a triangular face is found using the Pythagorean theorem. The apothem of the base and the height are legs of the right triangle whose hypotenuse is the slant height. For slant height x, we have ...

x² = 10² + a² = 100 +52.46

x ≈ √152.46 ≈ 12.35

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The area of the 8 triangular faces will be ...

A = 1/2Px . . . . where P is the perimeter of the pyramid

The area of the base will be ...

A = 1/2Pa

So, the total surface area is ...

A = 1/2P(a + x) = (1/2)(8)(6 cm)(7.24 +12.35 cm) ≈ 470.16 cm²

8 0

3 years ago

Read 2 more answers

What event would be complementary to the event that the product is an even number?

Phantasy [73]

The only possibility if a number is not even is that it is odd. Thus, the event would be the product is an odd number.

7 0

3 years ago

I need the answer to this please.

ohaa [14]

Answer:

Step-by-step explanation:

Its (1,3) and (-3, -2)

6 0

2 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

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3 years ago

Questions, are all in picture, please solve

Andrews [41]

The function represents a <em>cosine</em> graph with axis at y = - 1, period of 6, and amplitude of 2.5.

<h3>How to analyze sinusoidal functions</h3>

In this question we have a <em>sinusoidal</em> function, of which we are supposed to find the following variables based on given picture:

Equation of the axis - Horizontal that represents the mean of the bounds of the function.
Period - Horizontal distance needed between two maxima or two minima.
Amplitude - Mean of the difference of the bounds of the function.
Type of sinusoidal function - The function represents either a sine or a cosine if and only if trigonometric function is continuous and bounded between - 1 and 1.

Then, we have the following results:

Equation of the axis: y = - 1
Period: 6
Amplitude: 2.5
The graph may be represented by a cosine with no <em>angular</em> phase and a sine with <em>angular</em> phase, based on the following trigonometric expression:

cos θ = sin (θ + π/2)

To learn more on sinusoidal functions: brainly.com/question/12060967

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2 years ago