Answer:
![\frac{32}{243} \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B32%7D%7B243%7D%20%20%5C%5C%20)
Step-by-step explanation:
![= ( { \frac{2}{3})}^{5} \\ \\ = \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3} \times \frac{2}{3}](https://tex.z-dn.net/?f=%20%3D%20%28%20%7B%20%5Cfrac%7B2%7D%7B3%7D%29%7D%5E%7B5%7D%20%20%5C%5C%20%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%5Ctimes%20%20%5Cfrac%7B2%7D%7B3%7D%20)
Answer:
![(5\pi-11.6)ft^2](https://tex.z-dn.net/?f=%285%5Cpi-11.6%29ft%5E2)
Step-by-step explanation:
Given:
Length of radius of circle = 5 feets
Length of perpendicular bisector = 4 feets
To find:
Area of the shaded portion of the circle
Solution:
As OD is perpendicular bisector of AB,
![AB=2AD=2(2.9)=5.8\,\,feets](https://tex.z-dn.net/?f=AB%3D2AD%3D2%282.9%29%3D5.8%5C%2C%5C%2Cfeets)
![\angle ODA=90^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20ODA%3D90%5E%7B%5Ccirc%7D)
Area of
= 1/2 (base) × (height) =
square feets
Area of sector AOBC =
square feets
Here, r denotes radius of circle
So,
Area of shaded portion = Area of sector AOBC - Area of
=
Answer:
$14.50x.20= $2.90
Step-by-step explanation:
Im pretty sure it’s the last one....
1) Solving in terms of h
V = lwh <em>Divide both sides by h</em>
<em />
![\begin{gathered} V\text{ = lwh} \\ \frac{V}{h}=\frac{lwh}{h} \\ \frac{V}{h}\text{ =}lw\text{ Cross multiply} \\ hlw=V\text{ Divide both sides by lw} \\ \frac{hlw}{lw}=\text{ }\frac{V}{lw} \\ h\text{ = }\frac{V}{lw} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20V%5Ctext%7B%20%3D%20lwh%7D%20%5C%5C%20%5Cfrac%7BV%7D%7Bh%7D%3D%5Cfrac%7Blwh%7D%7Bh%7D%20%5C%5C%20%5Cfrac%7BV%7D%7Bh%7D%5Ctext%7B%20%3D%7Dlw%5Ctext%7B%20Cross%20multiply%7D%20%5C%5C%20hlw%3DV%5Ctext%7B%20Divide%20both%20sides%20by%20lw%7D%20%5C%5C%20%5Cfrac%7Bhlw%7D%7Blw%7D%3D%5Ctext%7B%20%7D%5Cfrac%7BV%7D%7Blw%7D%20%5C%5C%20h%5Ctext%7B%20%3D%20%7D%5Cfrac%7BV%7D%7Blw%7D%20%5Cend%7Bgathered%7D)
So rearranging that equation we can find h, in terms of V, and l and w.
If we want to solve in terms of l, or w, we'll proceed similarly to isolate the variable we want on the left side, and the other terms on the right side.