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julia-pushkina [17]
3 years ago
7

The potential difference in a simple circuit is 2 v and the resistance is 2 ω . what current flows in the circuit? answer in uni

ts of
a.
Physics
1 answer:
balandron [24]3 years ago
7 0
Hey

Potential Difference given is : 2V

Resistance is : 2 ohms

By Ohm's Law, one can easily utilize the relation :

v = ir

Where, { v , i , r } are the potential difference, current and Resistance Respectively.


Hence,
i =  \frac{v}{r}  =  \frac{2}{2}  = 1a

Hence, the Current is 1 Ampere
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I NEED HELP PLEASE! :)
Pachacha [2.7K]

Answer:

168 Hz

Explanation:

The Doppler equation describes how sound frequency depends on relative velocities:

fr = fs (c + vr) / (c + vs),

where fr is the frequency heard by the receiver,

fs is the frequency emitted at the source,

c is the speed of sound,

vr is the velocity of the receiver,

and vs is the velocity of the source.

Note: vr is positive if the receiver is moving towards the source, negative if away.

Conversely, vs is positive if the receiver is moving away from the source, and negative if towards.

Given:

fs = 164 Hz

c = 343 m/s

vr = -15 m/s

vs = -23 m/s

fr = fs (c + vr) / (c + vs)

fr = 164 Hz (343 m/s − 15 m/s) / (343 m/s − 23 m/s)

fr = 168 Hz

3 0
3 years ago
Find the current in amperes if 96 mC of charge pass through a wire in 8.4 s.​
olganol [36]

Answer:

Approximately 11.43

Explanation:

Using the formula charge=current×time

then current=charge/time. That then will be C=96/8.4=11.4285714286 so approximately 11.43

6 0
3 years ago
A 10 kg cart is rolling across a parking lot with a velocity of .5 m/s. What is its momentum?
-Dominant- [34]

Hello!

\large\boxed{p = 5  \text{ } kgm/s}

Use the equation for momentum:

p = mv

Plug in the given mass and velocity into the equation:

p = 10 * 0.5

p = 5 kgm/ s

4 0
3 years ago
A speed boat travels with a speed of 6 m/s travels directly north to cross a river flowing west with a current traveling at a sp
dedylja [7]

Answer:

6.7 m/s @ 116.6°

Explanation:

Use Pythagorean theorem to find the magnitude:

v² = vx² + vy²

v² = (-3 m/s)² + (6 m/s)²

v = √45 m/s

v ≈ 6.7 m/s

Use trigonometry to find the direction:

θ = atan(vy / vx)

θ = atan(6 m/s / -3 m/s)

θ = atan(-2)

θ ≈ 116.6° from the +x axis, or 63.4° north of west.

6 0
4 years ago
An object moves with a constant velocity of 17 m/s for 200 s. How far did it move during that time?
Radda [10]

17m/s for 200s

200 x 17 = 3400m

Answer: 3400m or 3.4km

6 0
3 years ago
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