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AleksAgata [21]
4 years ago
14

Several paper clips dangle from the north pole of a magnet. The induced pole in the bottom of the lowermost paper clip is a

Physics
1 answer:
sammy [17]4 years ago
4 0

I wanna say it’s B.

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What is defect of vision​
Anuta_ua [19.1K]

Answer:

The vision becomes blurred due to the refractive defects of the eye. There are mainly three common refractive defects of vision. These are (i) myopia or near-sightedness, (ii) Hypermetropia or far – sightedness, and (iii) Presbyopia. These defects can be corrected by the use of suitable spherical lenses.

4 0
3 years ago
If we are viewing the atom in such a way that the electron's orbit is in the plane of the paper with the electron moving clockwi
Anastaziya [24]

Answer:

The magnitude  of the electric field is 5.1 \times 10^{11}  \frac{N}{C}

Explanation:

Given:

Charge of electron q = 1.6 \times 10^{-19}C

Separation between two charges r = 5.3 \times 10^{-11} m

For finding the magnitude of the electric field,

   E= \frac{kq}{r^{2} }

Where k = 9 \times 10^{9}

   E = \frac{9 \times 10^{9} \times 1.6 \times 10^{-19} }{(5.3 \times 10^{-11} )^{2} }

   E = 5.1 \times 10^{11} \frac{N}{C}

Therefore, the magnitude  of the electric field is 5.1 \times 10^{11}  \frac{N}{C}

5 0
4 years ago
A bird flaps its wings 8 times per second. what is the frequency of the birds wing flapping?
Anika [276]

Answer:

480 flaps per minute

Explanation:

8*60 =480

7 0
3 years ago
Read 2 more answers
A material that resists the flow of electrons is called a(n)
laila [671]
A material that resists the flow of electrons is called an insulator.
4 0
3 years ago
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(TCO 4) A signal consists of only two sinusoids, one of 65 Hz and one of 95 Hz. This signal is sampled at a rate of 245 Hz. Find
storchak [24]

Answer:

65 Hz, 95 Hz, 150 Hz, 180 Hz, 310 Hz, 340 Hz

Explanation:

Given :

Frequencies of the sinusoids,

$f_{m_1}= 65 \ Hz$ ,  and

$f_{m_2}= 95 \ Hz$

Sampling rate f_s = \ 245 \ Hz

The positive frequencies at the output of the sampling system are :

$f_{o_1}=\pm f_{m_1} \pm nf_s, f_{o_2}=\pm f_{m_2} \pm nf_s $

When n = 0,

$f_{o_1}= f_{m_1} = 65 \ Hz,\ \  f_{o_2}= f_{m_2} = 95 \ Hz $

when n  = 1,

$f_{o_1}=\pm f_{m_1} \pm f_s, \ \ f_{o_2}=\pm f_{m_2} \pm  f_s $

$f_{o_1}= \pm 65 \pm 245,\ \  f_{o_2}=\pm 95 \pm 245$

$f_{o_1}= 180 \ Hz, 310 \ Hz,\ \  f_{o_2}= 150 \ Hz,340 \ Hz$

When n = 2,

$f_{o_1}= \pm 65 \pm 2(245),\ \  f_{o_2}=\pm 95 \pm 2(245)$

$f_{o_1}= 555 \ Hz, 425 \ Hz,\ \  f_{o_2}= 395 \ Hz,585 \ Hz$

Therefore, the first six positive frequencies present in the replicated spectrum are :

65 Hz, 95 Hz, 150 Hz, 180 Hz, 310 Hz, 340 Hz

8 0
3 years ago
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