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AleksAgata [21]
3 years ago
14

Several paper clips dangle from the north pole of a magnet. The induced pole in the bottom of the lowermost paper clip is a

Physics
1 answer:
sammy [17]3 years ago
4 0

I wanna say it’s B.

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Problem: Suppose that the rate of flow of water through a fire hose is 21.4 kg/s and the stream of water from the hose moves at
Sloan [31]

Answer:

The force exerted is 318.86 N

Explanation:

The force exerted by such a stream is calculated by multiplying the mass flow rate of water by the velocity of the stream of water.

mass flow rate = 21.4 kg/s

velocity = 14.9 m/s

Force exerted = 21.4 kg/s × 14.9 m/s = 318.86 kgm/s^2 = 318.86 N

6 0
3 years ago
Read 2 more answers
A +2.00nc point charge is at the origin, and a second -5.00nc point charge is on the x-axis at x = 0.800m find the magnitude of
Damm [24]
You have to reduce 2.00 an5.00 I order to use the×that=0.800
3 0
2 years ago
Two men decide to use their cars to pull a
Ulleksa [173]
The resultant force in the direction the truck is headed is:

734N*cos(31) + 1084N*cos(23)
629N+998N = 1627N
7 0
3 years ago
An initially motionless test car is accelerated to 115 km/h in 8.58 s before striking a simulated deer. The car is in contact wi
hoa [83]

Answer:

a)       a = 3.72 m / s², b)    a = -18.75 m / s²

Explanation:

a) Let's use kinematics to find the acceleration before the collision

             v = v₀ + at

as part of rest the v₀ = 0

             a = v / t

Let's reduce the magnitudes to the SI system

              v = 115 km / h (1000 m / 1km) (1h / 3600s)

              v = 31.94 m / s

              v₂ = 60 km / h = 16.66 m / s

l

et's calculate

             a = 31.94 / 8.58

             a = 3.72 m / s²

b) For the operational average during the collision let's use the relationship between momentum and momentum

            I = Δp

            F Δt = m v_f - m v₀

            F = \frac{m ( v_f - v_o)}{t}

            F = m [16.66 - 31.94] / 0.815

            F = m (-18.75)

Having the force let's use Newton's second law

            F = m a

            -18.75 m = m a

             a = -18.75 m / s²

4 0
2 years ago
A(n) 1946 kg car travels at a speed of 10 m/s . What is its kinetic energy ? Answer in units of J.
erica [24]

Answer:

KE=97300J

Explanation:

KE=1/2mv^2

KE=1/2(1946)(10)^2

KE=97300J

4 0
3 years ago
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