Vaporization and Production of bubbles. Production of heat and melting are physical changes
I am pretty sure it was composed of mostly CO₂.
Answer:
Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.
Explanation:
Step 1: data given
Reactants are Solid Mg(OH)2 and H2O(l)
Kc1 = 1.8 * 10^-11
Step 2: The balanced equation
Mg(OH)2(s) ⇄ Mg2+(aq) + 2OH-(aq)
Step 3: Define the equilibrium constant Kc
Kc = [OH-]²[Mg^2+]
Pure solids and liquids do not have any effect or influence on the equilibrium in the reaction. So they are not included in the equilibrium constant expression.
This means Mg^2+ and OH- are the chemical species present at the equilibrium. Mg(OH)2 will not affect the equilibrium.
Answer:
The new volume is 7.27 L
Explanation:
Step 1: Data given
The initial volume of the balloon = 7.0 L
The pressure = 765 mmHg = 765/760 atm = 1.00658 atm
The pressure drops to 737 mmHg = 737/ 760 atm = 0.969737
The temperature remains constant
Step 2: Calculate the new volume
P1*V1 = P2*V2
⇒with P1 = the initial pressure in the balloon = 765 mmHg
⇒with V1 = the initial volume = 7.0L
⇒with P2 = the decreased pressure = 737 mmHg
⇒with V2 = the new volume = TO BE DETERMINED
765 mmHg * 7.0 L = 737 mmHG * V2
V2 = (765 mmHG * 7.0 L) / 737 mmHG
V2 = 7.27 L
The new volume is 7.27 L
Answer:
The order of some common metals in the electromotive series, starting with the most easily oxidized, is: lithium, potassium, calcium, sodium, magnesium, aluminum, zinc, chromium, iron, cobalt, nickel, lead, hydrogen, copper, mercury, silver, platinum, and gold.
Explanation:
