The Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. Assume that the rope and pu
lley are massless and that there is no friction in the pulley. If the masses have the values m1=21.1 kg and m2=12.9 kg, find the magnitude of their acceleration ???? and the tension T in the rope. Use ????=9.81 m/s2.
1 answer:
Answer:
T=157.06 N
Explanation:
Given that
Mass of first block = 21.1 kg
Mass of second block = 12.9 kg
First mass is heavier than first that is why mass second first will go downward and mass second will go upward.
Given that pulley and string is mass less that is why both mass will have same acceleration.So lets take their acceleration is 'a'.
So now from force equation
21.1 x 9.81 - 12.9 x 9.81 =(21.1+12.9) a
Lets tension in string is T
T=21.1(9.81-2.36) N
T=157.06 N
You might be interested in
Answer:
Solution:
As per the question:
Temperature,
Pressure,
Therefore, from the eqn:
We can write:
Thus
where
= Exit temperature
Answer:
F = 2000 N
Explanation:
According to Newton's Second Law of Motion, the rate of change of momentum is equal to the force applied. Therefore, the formula written below will be used to solve this problem:
where,
F = Force everted = ?
ΔP = Cange in Momentum = 3000 N.s
t = time taken = 1.5 s
Therefore,
<u>F = 2000 N</u>
Given equations:
Substitute 3 for y in equation (1);
Substitute 3 for y in equation (3);
Adding equation (4) and (5);
Substitute 2 for x in equation (4);
Therefore, the values of (x,y,z) is (2,3,2).