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emmainna [20.7K]
3 years ago
10

As sound waves move from air to glass, the wave property of ________ will cause the wave to bend in that direction

Physics
1 answer:
Zarrin [17]3 years ago
5 0
<span>The amplitude because that controls the height of the wave. Correct answer: Amplitude.</span>
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zloy xaker [14]

Answer:

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Explanation:

6 0
2 years ago
A 20000 kg railroad car is rolling at 1.00 m/s when a 1000 kg load of gravel is suddenly dropped in. part a what is the car's sp
Talja [164]
Using conservation of energy and momentum we get m1*v1=(m1+m2)*v2 so rearranging for v2 and plugging the given values in we get:
(200000kg*1.00m/s)/(21000kg)=.952m/s
8 0
3 years ago
Do you think there could be another period of time when so many brilliant discoveries are made in such a span of time? Why or Wh
Arada [10]

There won't be another period where many brilliant discoveries are made in such a span of time because of the high degree of advancement already.

<h3>What is Technology?</h3>

Tgis is defined as the application of scientific knowledge for practical purposes.

We have advanced technological advancement which is why there won't be many discoveries in such time span.

Read more about Technology hee brainly.com/question/7788080

8 0
1 year ago
SOMEONE PLSSSS HELP ME WITH THIS QUESTION!!
Hitman42 [59]
The answer is indeed B
4 0
3 years ago
An ore sample weighs 17.50 N in air. When the sample
zysi [14]

Answer with Explanation:

We are given that

Weight of an ore sample=17.5 N

Tension in the cord=11.2 N

We have to find the total volume and the density of the sample.

We know that

Tension, T=W-F_b

F_b=buoyancy force

T=Tension force

W=Weight

By using the formula

11.2=17.5-F_b

F_b=17.5-11.2=6.3 N

F_b=V_{object}\times \rho_{water}\cdot g

Where

V_{object}=Volume of object

\rho_{water}=1000 kgm^{-3}=Density of water

g=9.8 ms^{-2}=Acceleration due to gravity

Substitute the values then we get

6.3=9.8\times 1000\times V_{object}

V_{object}=\frac{6.3}{9.8\times 1000}=6.43\times 10^{-4} m^3

Volume of sample=6.43\times 10^{-4} m^3

Density of sample,\rho_{object}=\frac{Mass}{volume_{object}}

Where mass of ore sample=1.79 kg

Substitute the values then, we get

\rho_{object}=\frac{1.79}{6.43\times 10^{-4}}=2.78\times 10^3 kg/m^3

Density of the sample=2.78\times 10^{3} kgm^{-3}

7 0
3 years ago
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