All categories

3 years ago

Factor the expression. k2 + kf – 2f2

2 answers:

5 0

Work: k^2+kf-2f^2
Factor
(K+2f)(k-f)
Answer: (k+2f)(k-f)
Check your work:
K+2f k-f
K^2+2kf-kf-2f^2
K^2+kf-2f^2

The answer is correct

Alex73 [517]3 years ago

5 0

Answer:

Factorized form of the given expression is (k + 2f)(k - f).

Step-by-step explanation:

The given expression is k² + kf - 2f² and we have to factorize the given expression.

k² + kf - 2f² = k² + 2kf - kf - 2f²

= k(k + 2f) - f(k + 2f)

= (k + 2f)(k - f)

So the factorized form of the expression is (k + 2f)(k - f).

You might be interested in

Write the rate in simplest form 168/8

Dafna1 [17]

168 / 8 = 21. It is in simplest form at 21.

3 0

3 years ago

The diagonals of a kite have lengths of x inches and 18x inches. The area of the kite is given by A=9x^2. Identify the equation(

Firdavs [7]

Answer:

Step-by-step explanation:

5 0

3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

3 years ago

Evan plant grass in a rectangular space behind the clubhouse

Nastasia [14]

A= l x b
70 = 14b
divide both sides by 14
b= 5

6 0

3 years ago

Help !!!!!!!!!! i need somebody to answer this

Mademuasel [1]

Answer:

Step-by-step explanation:

because it says between 4 and 8 and doesn't have a negative so its positive

7 0

3 years ago

Read 2 more answers