Answer:
There will be negative acceleration.
Explanation:
I majored in Physics
<u>Answer</u>
So this is the reaction that happens.
<span>C4H10 + O2 = CO2 + H2O </span>
<span>Balanced, it is </span>
<span>2C4H10 + 8O2 = 8CO2 + 10H2O </span>
<span>Given 1 kg or 1000 g of butane, use stoichiometry aka factor labeling aka conversions and mole ratios to get to grams of oxygen. </span>
<span>I'll do an example. Let's form water. Hydrogen is diatomic too. </span>
<span>2H2 + O2 = 2H2O </span>
<span>Given 1000 g of Hydrogen, I need to know how many grams of oxygen to use. To convert grams to moles,
I know that 1 mol of H2 equals 2.02 g. Then, for every mole of O2, there are 2 moles of H2. Then converting moles of O2 to grams, I know that one mole of it equals 32 grams. </span>
<span>[1000 g H2] x [1 mol H2/2.02 g H2] x [1 mol O2/2 mol H2] x [32 g O2/1 mol O2] </span>
<span>My answer would be 7.9 kg </span>
By definition titraion of a monoprotic acid with means that the equivalence point implies netrality of the solution, which is pH = 7.
So, the answer is that pH will be equal to 7 at the equivalence.
Given that the acid is monoprotic and KOH has one OH- radical per molecule of KOH, the titration will require the same number of moles of acid than base to reach the equivalence point, as you can see in this equation, representing the monoprotic acid as HA:
HA + KOH = K(+) + A(-) + H2O => 1 mol HA per 1 mol KOH.
Answer:
Mole fraction of C₄H₄S = 0.55
Explanation:
Mole fraction is moles of solute / Total moles
Total moles are the sum of moles of solute + moles of solvent.
Let's find out the moles of our solute and our solvent.
Mass of solute: 55g
Mass of solvent: 65g
Mol = Mass / molar mass
55 g / 84.06 g/mol = 0.654 moles of C₄H₄S
65 g /123 g/mol = 0.529 moles of C₂H₃BrO
Total moles = 0.654 + 0.529 = 1.183 moles
Mole fraction of thiophene = Moles of tiophene / Total moles
0.654 / 1.183 = 0.55
The answer would be 6 e-. This is becuase you are turning a charge of -4 into a +2. In order to do this, you transfer 4 electrons for a neutral charge, and an additional 2 for a charge of +2.
This makes a total charge of +2, and the total transferred electrons 6 e-