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Vesnalui [34]
3 years ago
5

What volume of 0.120 M HNO3(aq) is needed to completely neutralize 150.0 milliliters of 0.100 M NaOH(aq)?

Chemistry
1 answer:
True [87]3 years ago
7 0
HNO3 is a strong acid and NaOH is a
strong base. An equal number of moles of
each will create a neutral solution.
(.1500L)(.100M NaOH) = .01500 moles
NaOH, and therefore .015 moles OH-
.01500 moles H+ = .01500 moles HNO3 =
(.120M HNO3)(volume HNO3)
volume HNO3 = .125L HNO3, or 125mL
HNO3
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Given 50.0 grams of Strontium, find grams of Phosphorus required for complete reaction
Sveta_85 [38]

Answer:

                     Mass = 11.78 g of P₄

Explanation:

                     The balance chemical equation is as follow:

                                          6 Sr + P4 → 2 Sr₃P₂

Step 1: Calculate moles of Sr as;

Moles = Mass / M/Mass

Moles = 50.0 g / 87.62 g/mol

Moles = 0.570 moles

Step 2: Find moles of P₄ as;

According to equation,

6 moles of Sr reacted with  =  1 mole of P₄

So,

0.570 moles of Sr will react with  =  X moles of P₄

Solving for X,

X = 1 mol × 0.570 mol / 6 mol

X = 0.0952 mol of P₄

Step 3: Calculate mass of P₄ as,

Mass = Moles × M.Mass

Mass = 0.0952 mol × 123.89 g/mol

Mass = 11.78 g of P₄

8 0
3 years ago
Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re
laiz [17]

Answer:

80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.

Explanation:

From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.

6 0
3 years ago
What is equal to the number of particles in 36 grams of carbon-12?
HACTEHA [7]

Answer:

3 moles

Explanation:

To solve this problem we will  use the Avogadro numbers.

The number 6.022×10²³ is called Avogadro number and it is the number of atoms, ions or molecules in one mole of substance.  According to this,

1.008 g of hydrogen = 1 mole =  6.022×10²³  atoms.

18 g water = 1 mole = 6.022×10²³ molecules

we are given 36 g of C-12. So,

12 g of C-12 = 1 mole

24 g of C-12 =  2 mole

36 g of C-12 = 3 mole

So 3 moles of C-12 equals to the number of particles in 36 g of C-12.

4 0
3 years ago
A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil
Vaselesa [24]

Answer: 1.6L

Explanation:

V1 = 1.50 L,

V2 =?

n1 = 3mol

n2 = 3 + 0.2 = 3.2mol

From PV = nRT

V1 /n1 = V2/n2

1.5/3 = V2 /3.2

V2 = (1.5/3/) x 3.2 = 1.6L

5 0
3 years ago
Read 2 more answers
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vredina [299]

Answer:

Dependent variable: If calcium is given, then bone strength will increase.

Explanation:

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