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Yuri [45]
4 years ago
5

Vitamin is an organic compound whose deficiency in the human body can cause apathy, irritability, and an increased susceptibilit

y to infections. Below is an incomplete Lewis structure, for vitamin . Complete the Lewis structure and answer the following questions. [Hint: Vitamin can be classified as an organic compound (a compound based on carbon atoms). The majority of Lewis structures for simple organic compounds have all atoms with a formal charge of zero. Therefore, add lone pairs and multiple bonds to the structure below to give each atom a formal charge of zero.]
Chemistry
1 answer:
Mnenie [13.5K]4 years ago
7 0

Answer:

a) 21 bonds , and 4 bonds

b) bond angles , a < 109.5° , b ≈ 120° c < 109.5° d,e < 120° f ≈ 120° g ≈ 109.5°

c) 6 carbon atom are sp² hybridized

d) two carbon atoms are sp³ hybridized,

    two oxygen atoms are sp³ hybridized

    Nitrogen is not sp³ hybridized , it has sp² hybridization

e) vitamin B6 exhibit delocalized bonding, because the three double bond in ring are delocalized over 5 carbon atoms and one nitrogen atom , they are formed due to  6 p orbitals of 5 carbons and 1 Nitrogen atom. The bonding in vitamin B6  is similar to the Benzene.

Explanation:

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1) Ca-37, with a half-life of 181.1(10) ms.
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4 years ago
What is the valency of Aluminium and nitrate in Al(NO3)3 ?​
Kitty [74]

Answer:xl/ck xLKsx

Explanation:sl/cs c/ls

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3 years ago
Students investigating chemical reactions conducted the experiment you see here. An antacid tablet was dropped into a plastic ba
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3 years ago
50.0 mL of 0.200 M HNO2 is titrated to its equivalence point with 1.00 M NaOH. What is the pH at the equivalence point?
yKpoI14uk [10]

Answer:

8.279

Explanation:

The pH can be determined by hydrolysis of a conjugate base of weak acid at the equivalence point.

At the equivalence point, we have

$n_{NaOH}=n_{HNO_2}$

           = 25.00 x 0.200

           = 5.00 m-mol

           = 0.005 mol

Volume of the base that is added to reach the equivalence point is

$\frac{0.005}{1.00} \times 1000= 5.00 \ mL$

Number of moles of $NO^-_{2}=n_{HNO_2}$

                                           = 0.005 mol

Volume at the equivalence point is 25 + 5 = 30.00 mL

Therefore, concentration of $NO^-_{2}= \frac{5}{30}$

                                                        = 0.167 M

Now the ICE table :

            $NO^-_2 + H_2O \rightarrow HNO_3 + OH^-$

I (M)       0.167                   0            0

C (M)         -x                      +x          +x

E (M)      0.167-x                  x           x

Now, the value of the base dissociation constant is ,

$K_w=K_a \times K_b$            $(K_w \text{ is the ionic product of water })$

$K_b =\frac{K_w}{K_a}$

$K_b =\frac{1 \times 10^{-14}}{4.6 \times 10^{-4}}$

    = $2.174 \times 10^{-11}$

Base ionization constant, $K_b = \frac{\left[HNO_2\right] \left[OH^- \right]}{\left[NO^-_2 \right]}$

$2.174 \times 10^{-11}=\frac{x^2}{0.167 -x}$

$x= 1.9054 \times 10^{-6}$

So, $[OH^-]=1.9054 \times 10^{-6 } \ M$

pOH =- $\log[OH^-]$

       = $- \log(1.9054 \times 10^{-6} \ M)$

        =5.72

Now, since pH + pOH = 14

           pH = 14.00 - 5.72

                = 8.279

Therefore the ph is 8.279 at the end of the titration.

8 0
3 years ago
Choose the larger atom from each pair, if possible.
Ksivusya [100]

Answer:

a. Sn or Si ⇒ Sn

b. Br or Ga ⇒ Ga

c. Sn or Bi ⇒ similar in size

d. Se or Sn ⇒ Sn

Explanation:

The larger atom has a larger atomic radius. We have to consider how varies the atomic radius for chemical elements in the Periodic Table. In a group (column), the atomic radius increases from top to bottom while in a period (file), it increases from right to left.

a. Sn or Si ⇒ Sn

They are in the <u>same group</u>. Sn is on the top, so it has a larger atomic radius.

b. Br or Ga ⇒ Ga

They are in the <u>same period</u>. Ga is located at the left so it has a larger atomic radius.

c. Sn or Bi ⇒ similar

They are not in the same group neither the same period. Bi is located more at the bottom, so it would be larger than Sn, but Bi is also at the right side, so it would be smaller than Bi. Thus, they have comparable sizes.

d. Se or Sn⇒ Sn

They are not in the same group neither the same period. Se is located at the top and right side compared to Sn, so Sn is the larger atom.

3 0
3 years ago
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