When U-238 undergoes radioactive decay by losing an alpha particle, the other product is
2 answers:
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Answer:
The fraction of the volume of the atom that is taken up by the nucleus is .
The density of a proton is .
Explanation:
Diameter of the atom ,d = 2.50 Å
Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å
Volume of the sphere=
Volume of atom = V
..[1]
Diameter of the nucleus ,d' =
Radius of the nucleus ,r' = 0.5 d'=
Volume of nucleus = V'
..[2]
Dividing [2] by [1]
The fraction of the volume of the atom that is taken up by the nucleus is .
Diameter of the proton ,d =
1 m = 100 cm
Radius of the proton,r = 0.5 d=
Volume of the sphere=
Volume of atom = V
Mass of proton, m = 1.0073 amu =
Density of the proton : d
The density of a proton is .