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Dafna11 [192]
3 years ago
6

If an atom of chlorine had an atomic mass of 17 and it gained an electron what would you have?

Chemistry
1 answer:
Sonbull [250]3 years ago
4 0
The atomic mass would not change since the mass of an electron is negligible compared to the mass of protons and neutrons
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I need to find the chemical equation
Yuri [45]

Answer:

2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Explanation:

Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.

4 0
3 years ago
Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve
Alex73 [517]
The answer is 1.5*10^-12 square meters. For a detailed calculation, please refer to the attachment.
Download docx
7 0
3 years ago
Explain your observations in term of how tempurature affects paritcle motion and how liquid changes to a solid
Rus_ich [418]

Answer:

See explanation

Explanation:

Temperature is defined as a measure of the average kinetic energy of the molecules of a body.

When a substance is heated, the kinetic energy of its molecules increases as the temperature increases; hence the particles of the substance moves faster with increasing temperature.

When heat is withdrawn from a liquid, the temperature decreases and the average kinetic energy of the molecules decreases. The molecules become less energetic hence the liquid changes into solid

4 0
3 years ago
A researcher studying the nutritional value of a new candy places a 4.90 g sample of the candy inside a bomb calorimeter and com
snow_lady [41]

Answer:

449730.879 cal/g

Explanation:

Given data:

Mass of sample = 4.9 g

Change in temperature  = 2.08 °C  (275.23 k)

Heat capacity of calorimeter = 33.50 KJ . K⁻¹

Solution:

C(candy) = Q/m

Q = C (calorimeter) × ΔT

C(candy) = C (calorimeter) × ΔT / m

C(candy) =  33.50 KJ . K⁻¹ × 275.23 K / 4.90 g

C(candy) = 9220.205 KJ / 4.90 g

C(candy) =  1881.674 KJ / g

It is known that,

1 KJ /g = 239.006 cal/g

1881.674 × 239.006 = 449730.879 cal/g

8 0
3 years ago
How many grams of carbon dioxide are produced when 16 g of methane and 48 g of oxygen gas combust
larisa [96]
I believe the correct answer is 11 g
6 0
2 years ago
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