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3 years ago

9

A student got 16 out of 20 questions right on a quiz. Did the student answer less or more than 80% and less or more than 75% cor

rectly?

2 answers:

Greeley [361]3 years ago

7 0

The test is 20 questions worth 5 points each
20×5=100
16×5=80
The student answered 80 % correctly.

Firlakuza [10]3 years ago

3 0

The student got more than 75% they got exactly 80%.

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A number is 4 hundred more than 14 2 . what is the number?

egoroff_w [7]

$n=number \\ \\ n=400+142 \\ \\ n=542$

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3 years ago

If alpha and beta are the zeroes of the polynomial 6x2+x-2 find the value og alpha/beta + beta/alpha

castortr0y [4]

$6x^2+x-2=6x^2+4x-3x-2=2x(3x+2)-1(3x+2)\\\\=(3x+2)(2x-1)\\\\3x+2=0\to x=-\frac{2}{3}\\\\2x-1=0\to x=\frac{1}{2}\\\\\alpha=-\frac{2}{3};\ \beta=\frac{1}{2}\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{-\frac{2}{3}}{\frac{1}{2}}+\frac{\frac{1}{2}}{-\frac{2}{3}}=-\frac{2}{3}\cdot\frac{2}{1}-\frac{1}{2}\cdot\frac{3}{2}=-\frac{4}{3}-\frac{3}{4}\\\\=-\frac{16}{12}-\frac{9}{12}=-\frac{25}{12}=-2\frac{1}{12}$

$use\ Vieta's\ formula:\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}=\frac{\alpha^2+2\alpha\beta+\beta^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=\frac{(\alpha+\beta)^2}{\alpha\beta}-2\\\\\alpha+\beta=\frac{-b}{a};\ \alpha\beta=\frac{c}{a}\\\\\frac{(\alpha+\beta)^2}{\alpha\beta}-2=\frac{\left(\frac{-b}{a}\right)^2}{\frac{c}{a}}-2=\frac{b^2}{a^2}\cdot\frac{a}{c}-2=\frac{b^2}{ac}-2$

$6x^2+x-2\\\\a=6;\ b=1;\ c=-2\\\\\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{1^2}{6\cdot(-2)}-2=\frac{1}{-12}-2=-2\frac{1}{12}$

7 0

3 years ago

write two equations that when graphed look like this *see image*. please help its due soon and i will give ya 75 points for answ

Zigmanuir [339]

The graph is showing the equation of circle x²+y²=4

<h3>What is a circle?</h3>

A circle is a two-dimensional geometry on the plane having a centre point and the circular line is drawn equidistant from the centre point.

The given graph in the question represents the equation of the circle cutting the points on the x-axis and y-axis at 4 which is the radius of the circle.

The equation will be as follows:-

x²+y²=4

Hence the graph is showing the equation of circle x²+y²=4

To know more about circles follow

brainly.com/question/24375372

#SPJ1

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2 years ago

List the sides of triangle ΔMNP in ascending order (shortest to longest) if: Chapter Reference a m∠M = 64°, m∠N = 48°

scoray [572]

The given angles are
M = 64
N = 48
where P is unknown. While we don't know P at first, we can solve for it. Recall that for any triangle, the three angles always add to 180 degrees

M+N+P = 180
64+48+P = 180
112+P = 180
112+P-112 = 180-112
P = 68

-------------------------------------------

So in summary so far
M = 64
N = 48
P = 68

The shortest side is opposite the smallest angle. The side MP is opposite the smallest angle N = 48

The longest side is going to be opposite the largest angle. In this case, side MN is opposite the largest angle P = 68

The medium side is opposite the medium angle. So NP is the medium side length

-------------------------------------------------------

Final Answers:
Shortest Side = MP
Medium Side = NP
Longest Side = MN
See the attached image for a visual summary

The ascending order would be: MP, NP, MN

Note: Something like MP is the same as PM. The order of endpoints for any given individual segment doesn't matter

6 0

3 years ago

If sin theta = -1/2 and lies in the third quadrant, what is the cos?

never [62]

Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.

The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.

So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

$cos \: 30\degree = \sqrt{3} \div 2$

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).

$cos \: 210 \degree = - \sqrt{3} \div 2$

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3 years ago