Note that perimeter of rectangle ![P=2l+2w](https://tex.z-dn.net/?f=P%3D2l%2B2w)
So we have to solve for width or w.
![P=2l+2w](https://tex.z-dn.net/?f=P%3D2l%2B2w)
![30=2\times10+2w](https://tex.z-dn.net/?f=30%3D2%5Ctimes10%2B2w)
![w=5](https://tex.z-dn.net/?f=w%3D5)
Width of a rectangle is 5 units.
Hope this helps.
r3t40
The # 1 the answer is A
# 2 C
|x + 11| = 8
x + 11 = 8
<u> -11 -11</u>
x = -3
|3x - 2| = 16
3x + 2 = 16
<u> -2 -2</u>
<u>3x</u> = <u>14</u>
3 3
x = 4 2/3
Answer:
x = 2
Step-by-step explanation:
x + 5 = 2x + 3 ( subtract x from both sides )
5 = x + 3 ( subtract 3 from both sides )
2 = x
Answer:
The approximate volume of the tube is 1,005 cm³
Step-by-step explanation:
To find the volume of the tube, we will follow the steps below:
First, write the formula for calculating the volume of a cylinder
volume of a cylinder = πr²h
where r is the radius and h is the height of the cylindrical cardboard tube
from the question given, height is equal to 20 centimeters and diameter = 8 centimeters but diameter = 2r, this implies that r = d/2 hence radius r =8/2 = 4 centimeters
π is a constant and is ≈ 3.14
we can now proceed to insert the values into the formula
volume of a cylinder = πr²h
≈ 3.14 × 4²× 20
=3.14 × 16× 20
≈1,005 cm³ to the nearest whole cubic centimeter.
The approximate volume of the tube is 1,005 cm³