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Aleksandr [31]
3 years ago
15

What is 33/7 as a mixed number

Mathematics
2 answers:
melamori03 [73]3 years ago
5 0
33/7 is an improper fraction. 

To make it a mixed fraction, do this:-

How many times does 7 go into 33?

About 4 times.

4*7 = 28

4 is our whole number.

Now, subtract to get the numerator. 

33-28 = 5

4    5/7

Final answer:  4  5/7
Olenka [21]3 years ago
5 0
To write \frac{33}{7} as a mixed number we will do the following:-

33 ÷ 7 = 4 R5

Now lets write this as a whole number:-

4\frac{5}{7}.

CHECK OUR WORK:-

4\frac{5}{7}

7 × 4 = 28
28 + 5 = 33
33/7
We were RIGHT!!

So, 33/7 as a mixed number is 4\frac{5}{7}.

Hope I helped ya!! 
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2 years ago
Describe and correct the error in finding the tenth term of the arithmetic sequence 4, 12, 20, 28.
ycow [4]

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

a_n = a_1 + d(n-1)

Plug in a_1 = 4, \ d = 8, \ n = 10 and you should get the following:

a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\

The tenth term is <u>76</u>

---------

We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}

---------

In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in a_n = a_1 + d(n-1) which shifts everything one spot to the left.

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Step-by-step explanation:

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