Answer:
The answer is B
Step-by-step explanation:
Ed2020
Try this solution:
1. for probability of both televisions work:

2. for probability of at least on is defective (it means, the sum = one is defective and two are defective):
- for P(1defective);
- for P(2defective);
totaly for at least one is defective:

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Step-by-step explanation:
(a)
ii.
21 - 5 = 16 play only chess.
iii.
23 - 5 = 18 play only cards
5 play both.
that is 16+18+5 = 39 that play at least one of these games.
i.
so, 45 - 39 = 6 don't play any of these games.
(b)
we have 16+18 = 34 pupils out of 45 that play exactly one game.
so the probabilty to pick one of them is as usual
desired cases / total cases = 34/45 =
= 0.755555555... ≈ 0.76
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hot sauce: 80
taco: 400