Question

What is the value of x to the nearest tenth?

Answer 1

Step-by-step explanation:

Hello!!!

Let's workout with this figure.

BC is a chord, O is the centre and OA is the perpendicular bisector.

AB = 1/2 of BC (according to circle's theorem)

so, A B = 1/2 × 25.6

Therefore, the measure of AB is 12.8.

now, let's have a small work with triangle AOB.

as it is a Right angled triangle, taking angle B as refrence angle we get,

p=x

b=12.8

h= OB = 16 (it is also a radius.)

now,

by Pythagoras relation we get,

$p = \sqrt{ {h}^{2} - {b}^{2} }$

or, x = root 16^2- 12.8 ^2

by simplification, we get;

the measure of x is 9.6.

Therefore, the value of x is 9.6.

Hope it helps...